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i need help finding the position(relitive to the position at t=0) and velocity of the particle...
Find the position and velocity of a particle at t = 1.98 s if the particle is initially moving east at a speed of 19.8 m/s and experiences an acceleration of magnitude 4.40 m/s2, directed west.
Find the position and velocity of a particle at t = 1.98 s if the particle is initially moving east at a speed of 18.8 m/s and experiences an acceleration of magnitude 3.64 m/s2, directed west. Magnitude and direction of the position magnitude directionSelect Magnitude and direction of the velocity magnitude directionSelect
Find the position and velocity of a particle at t = 2.10 s if the particle is initially moving east at a speed of 19.8 m/s and experiences an acceleration of magnitude 4.20 m/s2, directed west. Magnitude and direction of the position. magnitude? direction? Magnitude and direction of the velocity. magnitude? direction?
The acceleration of a particle is a constant. At t = 0 the velocity of the particle is (14.0↑ + 14.9 your answers.) m/s. At t = 5.1 s te velocity is 1 1.4j m/s. (Use the following as necessary: t. Do not include units in (a) What is the particle's acceleration (in m/s)? a = | |- 2.75 | 1+1-0.69 j (b) How do the position (in m) and velocity (in m/s) vary with time? Assume the particle is...
A particle is moving with acceleration a(t) 36t +16. its position at time t0 is s(0) 12 and its velocity at timet0 is (0)-1. What is its position at time t- 12? Preview A particle is moving with acceleration a(t) 36t +16. its position at time t0 is s(0) 12 and its velocity at timet0 is (0)-1. What is its position at time t- 12? Preview
please i need help asap Problem 1 The acceleration of a particle moving only on a horizontal xy plane is given by a=3ti+4tj, where a is in meters per seconds squared and t is in seconds, at t=0, the position vector r=(20.0m)i+(40.0m)j locates the particles, which then has the velocity vector v=(5.00m/s)i+(2.00m's)j. at t=4.00s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?...
The position of a particle moving along an x axis is given by x 14.0t2 - 3.00t3, where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t = 3.00 s. (d) what is the maximum positive coordinate reached by the particle and (e) at what time is it reached? (f) what is the maximum positive velocity reached by the particle and (g) at what...
11. Review. A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.140 m/s and accel- eration -0.320 m/s. Suppose it moves as a particle under constant acceleration for 4.50 s. Find (a) its position and (b) its velocity at the end of this time interval. Next, assume it moves as a particle in simple harmonic motion for 4.50 s and x 0 is its equilibrium position. Find (c) its position and...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.60 s, the particle's velocity is vector v = (8.90 i + 7.70 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...
At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of vector v i = (3.00 i - 2.00 j) m/s and is at the origin. At t = 3.70 s, the particle's velocity is vector v = (7.40 i + 6.90 j) m/s. (Use the following as necessary: t. Round your coefficients to two decimal places.) (a) Find the acceleration of the particle at any time t. vector a = m/s2 (b)...