Question

The following raw data are final grades from an undergraduate statistics class. Use this data to answer table 1 76, 60, 80, 88, 93, 83, 97, 79, 97,85 Table 1. Mode Median Range 02 Interquartile range

Answer 1

Part III probability solution:

Z distribution has mean=0 and sd=1

Rcode:

library(tigerstats)

pnormGC(c(0,2.35),region="between",mean=0,sd=1,graph=TRUE)

Normal Curve, mean = 0, SD = 1 Shaded Area = 0.4906 density 0.2 0.4 0.0 2.35

ANSWER:

P(0.00<Z<2.35)=0.4906

Solution-b:

pnormGC(c(-2.10,2.34),region="between",mean=0,sd=1,graph=TRUE)

Normal Curve, mean = 0, SD = 1 Shaded Area = 0.9725 density 0.0 0.2 0.4 -2.1 2.34

ANSWER:

P(-2.10<z<2.34)=0.9725

Solution-c:

pnormGC(bound=0.13,region="above",mean=0,sd=1,graph=TRUE)

Normal Curve, mean = 0, SD = 1 Shaded Area = 0.4483 density 0.2 0.4 0.0 Fox

ANSWER:

P(Z>0.13)=0.4483

Solutiond:

Rcode:

pnormGC(bound=1.48,region="below",mean=0,sd=1,graph=TRUE)

Normal Curve, mean = 0, SD = 1 Shaded Area = 0.9306 density 0.2 0.4 0.0 1.48 Fox

ANSWER:

P(Z<1.48)=0.9306

Rscreenshot