answer is c =100 g
pure iodine are in 2 liters of a 1;20 iodine solution
first 2 L change into ml = 2000 ml
let pure iodine present be x
there fore
x/2000 = 1/20
x= 1 x 2000/20
x= 2000/20
x=100
so the answer is 100 g
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