Question

How many valence electrons are in Fe(NH₃)Cl₂Cp.

Answer 1

This is neutral complex.

[Fe(NH3) (Cl)2 Cp]

If C.N. = 6, then Cp should be tridentate then if we consider Cp as Cp^- then

C.M.I. Fe = +3

V. electrons on Fe³⁺ = 5 (3d5)

total valence electrons:

from Ionic method:

2 Cl^- = 4e

1 NH3 = 2e

1 Cp^- = 6 e

1 Fe³⁺ = 5e

Total will be : 17 electrons

From covalent method:

2 Cl^- = 4e

1 NH3 = 2e

1 Cp = 5 e

1 Fe²⁺ = 6e

Total will be 17 valence electrons.