Question

The angular speed of a propeller on a boat increases with constant acceleration from 14 rad/s...

The angular speed of a propeller on a boat increases with constant acceleration from 14 rad/s to 35 rad/s in 2.2 revolutions. What is the angular acceleration of the propeller?

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Answer #1

We know the equation of motion

omega _{f} ^{2} = omega _{i}^{2} + 2 alpha heta .............................(1)

Where, omega _{f} is final angular speed of the object

omega _{i} is initial angular speed of the object

  alpha is angular acceleration of the object

  heta is total angular distance covered by the object

Given,  

= 35 rad/s

  wi = 14 rad/s

  θ-2π × 2.2 13,823 rad (because in one revolution propeller covers a distance of 2 pi radians )

Putting all the values in equation (1), we get

(35)-= (14)2 + 2a × 13.823

or, 1225- 196 + 27.646 a

or, 27.6460-1029

or, a =-1029 27.646

or,   =37 22 rad/ s

Hence, the angular speed of the propeller is 37.22 rad/s2 .

For any doubt please comment and please give an up vote. Thank you.

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