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Q1. Compare the IR spectra of the alcohol and product and comment on the completion of the reaction and purity of the product collected. (4 pts.)

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Q3. Draw the structures of all products formed in your bromine test (4 pts)

Q4. Draw the structures of all products formed in your KMnO4 test (4 pts)Sinetanco 88 ES & 3 3 3 3 SRPEN 8 8 4000 3600 3000 1500 2500 2000 Wevenumbers (cm-1) 1000 Alcohol 8 8 8 88 gumus.1% 8 8 8 72

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Answer #1

Q1.

in alcohol the strong band at 3400 cm-1 is due to the hydroxy group, that is disappeared is almost disappeared in an alkene. therefore no alcohol is present in the product.

in the product, no band between 1600 - 1650 shows the absence of alkene also. therefore the product must be alkane and not alkene.

Q3.

if alkene is formed it will be decolorized the colour of bromine to form alkane dibromide as a product as shown below.

R BI - Y R Br

Q4.

if alkene is formed it will decolorize the color of KMnO4 to form dihydroxide as product.

R R, OH KMnO4 COH ROH

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