Question

5. Consider the apparatus shown in the figure to the right in which a conducting bar can be moved along two rails connected to a lightbulb. The whole system is immersed in a magnetic field fof magnitude B = 0.400 T perpendicular and into the page. The distance between the horizontal rails is l = 0.800 m. Th resistance of the lightbulb, R = 48.0 Ω, is assumed to be constant. The bar and rails have negligible resistance. The bar is moved toward the right by a constant force of magnitude F = 0.600 N. We wish to find the maximum power delivered to the lightbulb. (a) Find an expression for the current in the lightbulb as a function of magnetic field (B), current (l), resistance (R), and speed of the bar (v).

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(b) Find the numerical value for the speed of the bar when the maximum power is being delivered to the lightbulb.

(c) Find the current in the lightbulb when maximum power is being delivered.

(d) Using P = I2R, what is the maximum power delivered to the lightbulb?

(e) What is the maximum mechanical input power delivered to the bar by the force F?

(f) We have assumed the resistance of the lightbulb is constant. In reality, as the power delivered to the lightbulb increases, the filament temperature increases and the resistance increases. Does the speed found in part (b.) change is the resistance increases and all other quantities are held constant?

(g) If so, does the speed found in part (b.) increase or decrease? If not, explain.

(h) With the assumption that the resistance of the lightbulb increases as the current increases, does the power found in part (e.) change?

(i) If so, is the power found in part (e.) larger or smaller? If not, explain.

Answer 1

Please see image and try to understand thanks

B = 0.47 1:0.8m R-482 F = 0.6N ceas we know e emf e=dd y = - Bida es 8.2.dap = BUV dd dt = e =Bev т 0-40-өх max. power ext= Fiv -) (Bev)? = 0.6 XV - V- 5) ve 0.6 X UB (0-4)2 x (0-892 = 281.25 m Co ta BlvDu X08 * 281,25 = 1.875 Amp 48 I can P= I2R = 11.8752 x 48= 160.75 W mechanical power is same as above P=fv = 6.6*281.25 - 168.750 IR (increase Yes (f) here T9 =) R^ so. v= g var yes increase h I is depend on Resistance so I pafu speed 4 so p'= larger I is changes ↑ e S h a ....