A fully charged capacitor consists of parallel plates, which have an overlapping area of 4.00 mm2...
A fully charged capacitor consists of parallel plates, which have an overlapping area of 4.00 mm2 and are separated by a dielectric material with a relative permittivity of 4.50. The charge on the capacitor is 1.85 × 10-11 C. Calculate the strength of the electric field between the plates.
Homework Answers
Concepts used for the answer :- definition
of capacitance and relation between electric field and
potential.
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A fully charged capacitor consists of parallel plates, which
have an overlapping area of 4.00 mm2...
Constants Part A A capacitor consists of two parallel plates, each with an area of 15.0...
Constants Part A A capacitor consists of two parallel plates, each with an area of 15.0 cm2, separated by a distance of 0.250 cm. The material that fills the volume between the plates has a dielectric constant of 4.00. The plates of the capacitor are connected to a 200 V battery. What is the capacitance of the capacitor? SubmitPrev Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the charge on either plate? Part...
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Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1....
Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1.00 cm (1.00 x 104m) apart, we connect the capacitor to a power supply, charge it to a potential difference V。. 3.00kv, and disconnect the power supply. We then insert a sheet of insulating plastic material between the plates, completely filling the space between them. We find that the potential difference decreases to 1.00kV while the charge on each capacitor plate...
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Question 4 1 pts A parallel-plate capacitor of capacitance C has the area of plates A...
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A parallel plate capacitor is comprised of two metal plates with area A and separated by...
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Constants Part A A capacitor consists of two parallel plates, each with an area of 15.0 cm2, separated by a distance of 0.250 cm. The material that fills the volume between the plates has a dielectric constant of 4.00. The plates of the capacitor are connected to a 200 V battery. What is the capacitance of the capacitor? SubmitPrev Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B What is the charge on either plate? Part...
The charge on the 4.00 cm2 area plates of an air-filled parallel plate capacitor is such that the electric field is at the breakdown value. By what factor will the maximum charge on the plates increase when polystyrene is inserted between the plates? (The dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 2.40 x 107 V/m. The dielectric constant of polystyrene is 2.56. Supporting Materials Physical Constants Additional Materials Tutorial
Suppose the parallel plates in Fig. 24.15 each have an area of 2000 cm2 (2.00 x 101m2) and are 1.00 cm (1.00 x 104m) apart, we connect the capacitor to a power supply, charge it to a potential difference V。. 3.00kv, and disconnect the power supply. We then insert a sheet of insulating plastic material between the plates, completely filling the space between them. We find that the potential difference decreases to 1.00kV while the charge on each capacitor plate...
A parallel plate capacitor is made of plates of area 0.05 m? each. The plates are separated by a distance of 0.200 mm. Initially, the space between the plates is filled with air. (a) What is the capacitance of this air-filled capacitor? (b) If the electric field inside the capacitor exceeds 3.00 x 106 V/m, the air undergoes electrical break- down. (This maximum field is known as the dielectric strength of air.) From this, calculate the maxi- mum voltage (potential...
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