its applied engineering data analysis course
its applied engineering data analysis course Q1 A standard normal variable has a mean of zero...
its applied engineering data analysis course
Q2 A standard normal variable has a mean of zero and a variance of 1 ie. Z* N(0, 1). SKETCH THE AREA and find the following z that fulfills the probability: 1. P(Zsz) -0.1 2. P(Z2z or Zs-z) -0.1 3. At what value of z, the area to the right is 2.5%? 4. At what value of z, the area between-z and z is 68%?
its applied engineering data analysis course
Q3 A signal frequency measurement shows that frequency, X, is normally distributed with a mean of 100 and a variance of 5 ie X N (100, 5). SKETCH THE AREA and calculate the following probabilities: a. P(90 s X S125) b. P(X298) c. Find the x such that P(X Sx)-0.1 d. Find the range that contains the MIDDLE 90% of the observations: ie. find 'a, such that x is in [100-a, 100 + a]...
its applied engineering data analysis course
Q4 X is the diameter (in mm) of tires, normally distributed with mean 575 and a standard deviation of 5 SKETCH THE AREA of P(575 < X < 579) in both X and Z and find P Find the diameter x such that there are only 1% tires longer than this diameter ie. P[X>x] 0.01 Find the (diameters of) tires that have most extreme 5% diameters. a. b. C.
its Applied Engineering Data Analysis course
Question 2 options: Assume Z is a standard normal random variable with mean 0 and variance 1. Find P(Z<1.48)? Area below 1.48? Note: Enter X.XX AT LEAST ONE DIGIT BEFORE THE DECIMAL, TWO AFTER and round up. Thus, 27 is entered as 27.00, -3.5 is entered as -3.50, 0.3750 is entered as 0.38 | | Assume Z is a standard normal random variable with mean 0 and variance 1. Find P(Z>0.67)? Area above 0.67? Note: Enter X.XX AT LEAST ONE...
A) 0.7995 11. If Z is a standard normal variable find the probabilities of a) P(Z <-0.35)- @w B) 0.3982 C) 1.2008 D) p.4013 (2 points) b) P(0.25s Z<1.55) (3 points) c) P(Z > 1.55) (2 points) 12. Assume that X has a normal distribution with mean deviation .5. Find the following probabilities: 15 and the standard a) P(X < 13.50)- 3 points). b) P (13.25 <X < 16.50)- (5 points). B) 0 2706 C0 5412 D) 1.0824 A mountuin...
1. (5 points) Suppose Z is a random variable that follows the standard normal distribution. a) Find P(Z > 0.45). b) Find P(0.7 SZ 1.6). c) Find 20.09. d) Find the Z-score for having area 0.18 to its left under the standard normal curve. e) Find the value of z such that P(-2SZS2) -0.5. 3. (4 points) The scores on a test are normally distributed with a mean of 75 and a standard deviation of 8. a) Find the proportion...
2. Given that z is a standard normal random variable, compute the following probabilities. P(-1 ≤ z ≤ 0) (Round to four decimal places) Answer P(-1.5 ≤ z ≤ 0) (Round to four decimal places) Answer P(-2 < z < 0) (Round to four decimal places) Answer P(-2.5 < z < 0) (Round to four decimal places) Answer P(-3 ≤ z ≤ 0) (Round to four decimal places) 3. Given that z is a standard normal random variable, compute the...
Find the following probabilities for a standard normal variable, Z 1) P(Z<-1.27) 2) P(-2.03<Z<3.49) 3) P(Z>1.74) 4)P(Z<0.17) B. Find z if we know that the area to the left of z (under the normal curve) is 0.9265.
2. Random variable Z has the standard normal distribution. Find the following probabilities a): P[Z > 2] b) : P[0.67 <z c): P[Z > -1.32] d): P(Z > 1.96] e): P[-1 <Z <2] : P[-2.4 < Z < -1.2] g): P[Z-0.5) 3. Random variable 2 has the standard normal distribution. Find the values from the following probabilities. a): P[Z > 2) - 0.431 b): P[:<] -0.121 c): P[Z > 2] = 0.978 d): P[2] > 2] -0.001 e): P[- <Z...