Question

11. A male patient has an MCV 107.8 fL, RBC of 4.51 x1012, and an MCH-33.1 pg. a. What is his Het value? b. What is his HgB value? c Describe his RBC morphology d. Is he anemic (Y/N)? e. What's your basis of the assessment of anemia (Low HgB/Low Hct/Both low/Both normal)? Show your calculations:

Answer 1

1.Hct Value ( Hematoctit value)

Formula – MCV * RBC /10

Answer – 107.8*4.51/10 =48.61

Therefore the Hematocrit value of the given values is 48.6%

2. HgB Hemoglobin

Formula – MCH*RBC/10

Answer – 33.1*4.51/10 => 14.92

Hence the Hemoglobin is calculated by Multiplying MCH and RBC divided by 10 Is 14.92g/dl

3. RbC Morphology

Ans: Morphology is the study of form and structure of a cell, In the question the picture of RBC was not given to illustrate the Structure of RBC but From the laboratory values it reveals that the Person has RBC – 4.51million mcL, Hematocrit- 48.6 % and MCV 107.8fL and MCH – 33.1g.

From the Lab values the RBC is looks like slightly macrocytic in form and structure as evidenced by the MCV value 107.8fl ( Normal Value > 100fl )

4. Is he anemic

Answer : No, Because the The Hemoglobin is 14.92 Which is normal in range

( normal Value- 13.5 to 17.5 g/dl)

5. Basis for Assesing anemia

Answer

1. Size of red blood cells

2. Abnormal cells found on microscopic examination

3. Elevated LDH and Indirect bilirubin

4. Levels of leucocytes and platelets

5. Reticulocyte Rate

Size of RBC is calculated from MCV ( Mean CVell Volume)

Microcyttic < 80 fl

Normocytic 80-100 fl

Macrocytic >100fl

From the given values the clients RBC is slightly enlarged Macrocytic.