Question

Using the sequences of 32-bit memory read references, given as word addresses in the following table:...

Using the sequences of 32-bit memory read references, given as word addresses in the following table:

6

214

175

214

6

84

65

174

64

105

85

215

For each of these read accesses, identify the binary address, the tag, the index, and whether it experiences a hit or a miss, for each of the following cache configurations. Assume the cache is initially empty.

  1. A direct-mapped cache with 16 one-word blocks.
  2. A direct-mapped cache with two-word blocks and a total size of eight blocks.
  3. A fully associative cache with two-word blocks and a total size of eight words. Use LRU replacement.
  4. A 2-way set associative cache with one-word block size and total size of 8 words, while applying LRU replacement policy.
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Answer #1

Solution

B)

As per the question we assume cache is initially empty

total cache size = 8 blocks that means it using 2 word block

1 bit assigned for word offset,

3 bits assigned for block selection that means 3 bits for index, remaining is for Tag

Address (word)

Address(Hex)

Cache Tag

Index

Cache Data

Hit/Miss

6

0x00000000000110

0x0000000000

011

M(6) M(7)

Miss

214

0x00000011010110

0x0000001101

011

M(6) M(7) replaced by M(214) M(215)

Miss

175

0x00000010101111

0x0000001010

111

M(174) M(175)

Miss

214

0x00000011010110

0x0000001101

011

M(214) M(215)

Hit

6

0x00000000000110

0x0000000000

011

M(214) M(215) replaced by M(6) M(7)

Miss

84

0x00000001010100

0x0000000101

010

M(84) M(85)

Miss

65

0x00000001000001

0x0000000100

000

M(64) M(65)

Miss

174

0x00000010101110

0x0000001010

111

M(174) M(175)

Hit

105

0x00000001101001

0x0000000110

100

M(104) M(105)

Miss

85

0x00000001010101

0x0000000101

010

M(84) M(85)

Hit

215

0x00000011010111

0x0000001101

011

M(6) M(7) replaced by

M(214) M(215)

Miss

--

solved one question, really sorry for that

please post remaining question separately, love to answer

all the best

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