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mutation: sickle cell
Explain in terms of the listed mutation and structural elements, what causes polymerization of hemoglobin. Explain how polyme
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1) In sickle cell anemia, there is point mutation ( missing sense mutation) from T to A. This will replace beta chain N terminal 6 position glutamine to valine. As glutamate is a polar amino acid , is replaced by non polar amino acid valine. This causes a marked decreased solubility of HbS in deoxygenated form ( T form). However solubility of oxyhaemoglobin HbS is unaffected. This replacement of glutamate to valine leads to decrese in solubility of Hbs as well as their polymerization in deoxy form which lead to precipitation.

2) substitution of aljne for glutamate results in to sticky patches on the outer surface of beta chain. There sticky patches present on oxy as well as deoxy Hbs. But these patches are absent on HbA .

There are corresponding receptor for sticky patches on alpha subunit of other deoxy HbS. So patches of one deoxy Hbs , polymerize with receptor of othe deoxyHbs. This polymerization continues lead to formation of long aggregates of deoxyHbS. This polymerization leads to long fibrous like structure formation. As these fibers precipitate, due to their stiffness they distort RBC and convert them in to sickle shape and their lysis.

If this Hbs is maintained in to oxy form than this polymerization can be prevented due to absence of corresponding receptor on alpha chain.

Mechanism of polymerization has been explained below

Oxy nbs de otghor oxg hiba deoxgrba Patches lisse - Trunden ß chann Tuptor in ex cham 5 C Polynerization a deoxynos besos - P

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