Question

DV 18. For the formation of 1 mol of nitrosyl chloride at a given temperature, AH -36 kJ. NO(g) + Cl2(g) → NOCI(8) The activation energy for this reaction is 84 kJ/mol. What is the activation energy for the reverse reaction? A) -36 kJ/mol B) 48 kJ/mol C) 84 kJ/mol D) 120 kJ/mol E) -120 kJ/mol 19. The rate constant for a first-order reaction is 1.8 x 10° s at 736 K and 4.0 x 10s at 836 K. What is the activation energy? A) 18 kJ/mol B) 41 kJ/mol C) 4900 kJ/mol D) 40 kJ/mol E) 18 kJ/mol 20. For the first-order reaction YAN204(8) ► NO2(g); AH = 28.6 kJ the rate constant is k= 1.52 x 10ʻs' at -15°C, and the activation energy is 53.7 kJ/mol. What is the rate constant at 13°C? A) 2.86 x 10's! B) 1.77 x 106 1 C) 1.52 x 10 D) 1.69 x 10 51 E) 6.03 x 10's!

Answer 1

Pro the exothermie at the reaction is 18. For the Formation formation of of 1 mol 1 mol of nitrosal chloride of nitrosa value of AH indicate that the reaction is ex reaction. NO(g) + dela (g) Noel (8) Given that the activation energy for the ist 81 ker mort, For exothermic reaction, E - £, - AH tion energy for the forward reaction wherce, E, saetiva saetivation energy or forward redelion E2 = activation energy of bar reverse a reaction AD - E = E-DH - 84-(-36) = 84+36 = 120 The activation energy for the reverse reaction it 120 kJ mol-1 19. We know that, in (102) = () 51 Ši where, k, = reaction rate at 836k; i e; 4x102 Ką= reaction rate at 736 k; i e; 1.8x102 T= 836k. T2 = 736k Ea a activation energy to R = Universal constant a 8.314 I molt R. T2 T1 TT-T2) in (la ) Ea - -x ln 8.814 8836x736 (836-736) 1.8x152 - 40 848.227 Jmoii = 40.85 kJ/mol

20. We know that Pro 7172 where 4 = reaction state at 286k Ky = reaction rate at 258k = 1.52x10° s' T = 13°c =(273 +13) K = 286K Tz = -15°c = (273-15k = 258k Imol = 53.7x10 Jmoll fa= activation energy = 53,7 kJ/mol = 53.7 R = Universal constanta 8.314 Jmol 7 en ( k s ) = (286-258 x 53.7% 103 286 X 258 8.314 152 28 53.7x10 8. 314 2868258 = 2:45096 2145096 kl 10o = ( 2 => = 1.5995 Ki= 11.5995 * 1.52x106 07831210 somos = 12636240 g x 106 g Ĉ 17631240 251 = 1.7631240 X 1065 ã 1.77x10657