Question

HI GUYS CAN YOU HELP ME SOLVE THIS QUESTION ASAP PLS AND THANKS!! QUESTION 6 ONLY, THE 15 MARK QUESTION. CAN YOU CALCULATE THE THEOREATICAL VALUES WITH THESE 3 VALUES: 10HZ, 1KHZ, 10KHZ. AND USING THIS VALUES. R = 1000Ω,C = 1µF, L = 0.23mh. not the L=44 thanks.

Exercise 2 [60 marks] RLC Circuit as a Low-pass Filter L 0000 in out Figure 2. RLC circuit 2 10 marks] Derive the second order input-output model (differential equation) for the RLC circuit in Figure 2 with the voltage input x(t) and the voltage 4. Y(ω) output yt). Also, write down the frequency response function H(0)=- X (ω) 5. [20 marks] Connect the circuit as shown in Figure 2 with R 10002,C 1uF, L : 44T[Option A] R 1000,C 0.1uF,L:44T [Option B] Connect the input voltage to a function generator with a sinusoidal signal of pk-pk amplitude in the range 5-8V Record the input and output gain |H(w) |and the phase difference ZH(w) for three different frequencies selected between 10HZ and 10KHZ, representing low frequency, middle frequency, and high frequency, respectively 6. [15 marks] Calculate the theoretical values of |H(@)|and ZH(@) for the three frequencies used in Step 5, using the inductance of L from Exercise 1 ww

Answer 1

convent the circuit in to s-domain. - 3 Inductive Reactance x = Sl= 0.23x10 se Capacitive Reactance &c. sca n ostries I a 0.23x10's s) 10001 By using voltage Division Rule, usin xcex [ 1000x Totes Y(Sl= X (&x 1000+ Tots 0-23rios + 1000* Coco EM 1000 Itlo's 0.23x10st 1000 tos 1000 NA X (s) Too + 0.23x10 s + 0.23x10 put sajo. Y( 0) 1000 (w) X () – 0.23x10 + 50 23x5w+ 1000 looo Howl - - √ (1000 - 0.23 000 + (0.23xiows (10) - Tant (1800] - Tanto 0.23x10w 200 - 0.2s xiobor

f = 10 HE: = 271f 62.83 radlsec. 1000 le(wila - 7 999, 998.18 How) = – 8. 2 79x10. = 10oort: - w=21 f = 6283. 185 radfoec. 1000 - 1.009 lecol- 990.92 (HW) = – 0.0835. f = 10 uz :- w=21f - 62831.8s nad/sec. 1000 = 10.738 THW) = 93.12 (H2O) = – 8.927.