Question

Problem: A solution containing 50.0 mL of 0.100 M EDTA buffered to pH 10.00 was titrated with 50.0 mL of 0.020 0 M Hg(CIO4)2 in the cell [[ S.C.E || titration solution | Hg Ol]. From the cell voltage E = -0.027 V, find the formation constant of Hg(EDTA)2-. I know how it's done, but I have few questions from the solution below. What does F_EDTA mean? How do you get 0.30 at the bottom when calculating Kf? The following is the solution for Quantitative Chemical Analysis (9th Edition) by Daniel. The reaction in the silver electrode is Hg²+ + 2e 0 Hg(s), and the cell voltage is written as E=E.-E =E.-E(S.C.E) = E-0.241 -0027=(0,852 009 16.00 pm J-2211 love the 3-216 [Hgºt] =3x10-2 M The equation for Kf is seen below. HgY) kyng** ]ex Porn It can be assumed that [HgY2 and FEDTA are equal to what would occur with a quantitative complexation with Hg2+ since the actual [Hg2+] is very small. [Hgy?]=[*1.. [HgY²- ]=(50.0 mL)(0.020 0 M) = 1.00 mm Fiora = [EDTA... -[#g*. Flora = (50.0 mL)(0.100 M)-1.00 mm = 4.00 mm

Answer 1

Answer. FEDTA mean? How do get 10.30) at the bottom of kf calculation? ks for the problems given; formula is 1. As kp - [Hg yan] [Hg2+]ý4. FEDTA For pH less than 13, at any pH <13, the Concentration of LEDTA] formed is less than 100% of [EDTAJ. Due to which LEDTAJ" calculated as [EDTAJ4 = xy". FEDTA 24 = fraction of species dissociation of ly means EDTA. FEDTA = Total concentration of [EDTA] which is free in the solution. (non complexed {EDTA]) As xy-4 value at pHelo es xx-4 = 0.30 1 Kyry changes as pH change. i.e. why 0.30 is at the bottors when calculating EDTA-47