Question

4. Figure shows a power source that feeds a 100 kVA 14/2.4 kV transformer through a feeder with impedance of 100/60° Ω Load 90 kw 0.85 PF lagging Feeder transmission line) Source Transformer Load The transformer has been tested to determine its equivalent circuit. The results of the tests are: Open-circuit test Voc = 14 kV oc 0.1 A Рос-800 w Short-circuit test Vsc 800 V Isc = 7A Psc 2 kW The load on the transformer is 90 kW at 0.85 pf. and 2300 V What is the voltage at the power source of the system? What is the voltage regulation of the transformer? a. b. Page 1 C. How efficient is the overall power system? [Result: Vrce14.5/4.3° kV]

0 0
Add a comment Improve this question Transcribed image text
Answer #1


Determine the tums ratio, a of the transformer V] 14 kV 2.4 kV - 5.833 Determine the short circuit impedance angle from the sThe feeder impedance referred to secondary side is, 2400 ine14000 (100260°) -1.47+12545 Ω The second current i8, 90000 L-cos2300(46.032-31.78 - 2423+ j93.657 1.2+ j3.137) 2424.8/2.21° V Now calculate the voltage regulation of the transformer VR 2424

Add a comment
Know the answer?
Add Answer to:
4. Figure shows a power source that feeds a 100 kVA 14/2.4 kV transformer through a...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • please the power factors given in the question are different which are 0.8 and 0.85 please...

    please the power factors given in the question are different which are 0.8 and 0.85 please explain to me which one would be used in the calculations and why is it used? please I want a typed copy of it. b. A single-phase power system is shown below. The power source feeds a 100-kVA, 14/2.4 - kV transformer through a feeder impedance of 40.0 +j15022. The transformer's equivalent series impedance referred to its low-voltage side is 0.12 + j0.5 22....

  • Electric Machinery Problem 2: [50 points] A 15-KVA, 230/2300-V transformer is considered. The following test data...

    Electric Machinery Problem 2: [50 points] A 15-KVA, 230/2300-V transformer is considered. The following test data have been taken: | OC Test (on Primary) Voc = 230 V loc = 2.8 A Poc = 100 W SC Test (on Secondary) Vsc = 47 V Isc = 9.5 A Psc = 350 W (a) Find the equivalent circuit of this transformer referred to the high- voltage side. [10 points] (b) Find the equivalent circuit of this transformer referred to the low-...

  • Q No.1: A 14,000/130-V, three-phase, ∆-Y transformer bank consists of three identical 100-kVA, 83l4/130-V transformers. It...

    Q No.1: A 14,000/130-V, three-phase, ∆-Y transformer bank consists of three identical 100-kVA, 83l4/130-V transformers. It is supplied with power directly from a large constant voltage bus. In the short-circuit test, the recorded values on the high-voltage side for one of these transformers are Vsc = 510V,     Isc = 12.6 A,        Psc = 3000 W (a) If this bank delivers a rated load at 0.8 PF lagging and rated Voltage, what is the line-to-line voltage on the primary of the...

  • Choose the base power as 50-KVA, the primary base voltage as 2400-V, the secondary voltage as...

    Choose the base power as 50-KVA, the primary base voltage as 2400-V, the secondary voltage as 240-V: (a) Calculate and sketch the transformer equivalent circuit in per unit values' (b) The transformer is carrying rate load of 1.0 pu at.8 power factor lagging. Calculate the primary voltage in per unit. (c) Calculate the efficiency of the transformer at this load. A 50-KVA 2400/240-V, 60-Hz distribution transformer is tested with the following results: Open circuit Test Short Circuit Test Voc =...

  • A 2.2KVA 600/120 V, transformer has the following data for its OC test and SC test:...

    A 2.2KVA 600/120 V, transformer has the following data for its OC test and SC test: OC Test: Voc: 120V Ioc: 0.6A Poc: 16W SC Test Vsc = 12V Isc = 3.67A Psc= 30W (a) Find the equivalent circuit referred to its HV and LV side. (b) If it operating as a step-down transformer, and delivering its rated current at the rated voltage and 0.85 pf lagging, find what will be the input voltage. (c) Find the Voltage regulation of...

  • A 1200 kVA, 11/3.3 kV, 50-Hz, three phase Dyn 11 transformer is subjected to both the...

    A 1200 kVA, 11/3.3 kV, 50-Hz, three phase Dyn 11 transformer is subjected to both the open, and short circuit tests, yielding the following results: OPEN CIRCUIT TEST SHORT CIRCUIT TEST Vsupply = 3.3 kV Vsupply = 650 V Io = 7.3 A Isc = 54.4A Po = 6.71 kW Psc = 8.89 kW Determine: 1.1 The no load current per phase, in RECTANGULAR form, referred to the H.V. side. (5) 1.2 How would you know, without being told, that...

  • Solvein pu sysvem 2-10. A 13,800/480 V three-phase Y-A-connected transformer bank consists of thr...

    please solve the question in pu sysyem !!!! Solvein pu sysvem 2-10. A 13,800/480 V three-phase Y-A-connected transformer bank consists of three identical 100-kVA 967/480-V transformers. I is supplied with power directly from a large constant-voltage bus. In the short-circuit test, the recorded values on the high-voltage side for one of these transformers are Isc 12.6 A Pc3300 w (a) If this bank delivers a rated load at 0.85 PF lagging and rated voltage, what is the line-to-line voltage on...

  • The following data was obtained when open circuit and short circuit tests were performed on a...

    The following data was obtained when open circuit and short circuit tests were performed on a single phase, 50 KVA, 2,400:240 V, 60 Hz distribution transformer: With high voltage winding open circuited: Voc = 240 V, Ioc = 4.85 A, Poc = 173 W With low voltage winding short circuited: Vsc = 52 V, Isc = 20.8 A, Psc = 650 W a) Determine the equivalent circuit of the transformer referred to its high voltage side and to its low...

  • A 5 MVA 230/13.8 kV, single-phase transformer has a per-unit resistance of 1% and a per-unit...

    A 5 MVA 230/13.8 kV, single-phase transformer has a per-unit resistance of 1% and a per-unit reactance of 5%. The open-circuit test performed on the low voltage side of the transfromer yielded the following data: VOC=13.8 kV, IOC=21.1 A, and POC=90.8 kW. (a) Find the equivalent circuit referred to the high voltage side of this transformer. (b) If the transformer is operating at full-load and at 0.8 pf lagging, find the voltage regulation of the transformer at this operating condition.

  • Given a 31.5 MVA Single phase step down transformer.110 KV:11 KV The open circuit test values...

    Given a 31.5 MVA Single phase step down transformer.110 KV:11 KV The open circuit test values are Input voltage = 11 KV, P = 22.1 KW, I=5.85 A The short circuit test values are.Input voltage = 5.755 KV, P=163.935 KW, I= 286.36A If the transformer is run full load output with a power factor of 0.8 lagging 13.            Find I2 and V2     bold denotes phasor values 14.            Find the full load power P 15.            Find the voltage drop across the...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT