A 0.5998 sample of a new compound with a molar mass of 93.12 g/mol was analyzed...
Homework Answers
% C = (0.2322 / 0.5998) x 100 = 38.7
% O = (0.3091 / 0.5998) x 100 = 51.5
% H = 100 - 51.5 - 38.7 = 9.8
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0.5998 sample of a new compound with a molar mass of 93.12 g/mol
was analyzed...
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