Question

A diode is characterized by Is = 1x102 A and n Vr = 25 mV. i. Graph the diode response over the range VD = [0,0.65] Volts ii. Determine the AC resistance for VD=0.5 V. (5 points) iii. Determine the AC resistance for VD=0.64 V. (5 points) iv. Graph the diode response & the AC resistance response for VD = 0.64 V using Matlab. (5 points)

Answer 1

QUES:

ANS:

part (a)

clear all;close all;clc
%%Parameters and Formulation Part

i_saturation = 1.0e-12; % Saturation Current
V_diode = 0:0.01:0.65; % Voltage Sampling
n_Vt = 0.025 ;
i_d= i_saturation*exp(V_diode/n_Vt); % Diode Current at T1
%% Plotting the Results

plot(V_diode,i_d)
title('Diode I-V Curve ')
xlabel('Voltage (V)')
ylabel('Current (A)')

Result :-

Diode I-V Curve 0.2 0.18 0.16 0.14 0.12 0.1 0.08 0.06 0.04 0.02 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 Voltage (V) Current (A)

T (b) e L(acreitan.e) exelh 05v. 12 S1.5288 25 0.1905 ohm P/0-61 25

Ques. (D)

clear all;close all;clc
%%Parameters and Formulation Part

i_saturation = 1.0e-12; % Saturation Current
syms V_diode % Voltage Sampling
n_Vt = 0.025 ;
i_d= i_saturation*exp(V_diode/n_Vt); % Diode Current at T1
%% Plotting the Results
rd(V_diode) = 1/diff(i_d,V_diode)
V_diode = 0:0.01:0.65 ;
plot(rd(V_diode))
double(rd(0.64))
title('Ac resistance Curve ')
xlabel('Voltage (V)')
ylabel('ac resistance (Rd)')

Result:-

x10 10 2.5 Ac resistance Curve 2 1.5 0.5 0 0 10 30 40 70 Voltage (V) 60 50 20 ac resistance (Rd)