Homework Answers
8) cross is AABBCC * aabbcc
F1 progeny is AaBbCc
a) A/- B/- c/c
AaBbCc * AaBbCc
let`s divide this cross in to 3
Aa * Aa
| A | a | |
| A | AA | Aa |
| a | Aa | aa |
The proportion of A/-= number of Aa+number of AA/total number
= 2+1/4
= 3/4
Bb* Bb
| B | b | |
| B | BB | Bb |
| b | Bb | bb |
the proportion of B/-= 3/4
Cc*Cc
| C | c | |
| C | CC | Cc |
| c | Cc | cc |
proportion of cc= number of cc/total number
= 1/4
the proportion of A/- B/-cc= The proportion of A/-*the proportion of B/-*proportion of cc
= 3/4*3*4*1/4
=9/64
b) aabbcc
from the cross Aa* Aa
proportion of aa= number of aa/total number=1/4
from the cross Bb * Bb
proportion of bb= number of bb/total number=1/4
from the cross Cc* Cc
proportion of cc= number of cc/total number=1/4
proportion of aabbcc= proportion of aa * proportion of bb * proportion of cc
= 1/4*1/4*1/4
= 1/64
9) Probability of getting genotype AaBbCc
1) probability of getting Aa from the cross Aa * Aa = number of Aa/ total number
= 2/4
= 1/2
2 ) probability of getting Bb from the cross Bb * Bb = number of Bb/ total number
= 2/4
= 1/2
3) probability of getting Cc from the cross Cc * Cc = number of Cc/ total number
= 2/4
= 1/2
Probability of getting AaBbCc= probability of getting Aa from the cross Aa * Aa* probability of getting Bb from the cross Bb * Bb*probability of getting Cc from the cross Cc * Cc=1/2*1/2*1/2=1/8
b) probability of getting aabbcc=
Probability of getting aa from Aa* Aa= number of aa/total number=1/4
Probability of getting bb from Bb* Bb= number of bb/total number=1/4
Probability of getting cc from Cc* Cc= number of cc/total number=1/4
probability of getting aabbcc= Probability of getting aa from Aa* Aa* Probability of getting bb from Bb* Bb*Probability of getting cc from Cc* Cc=1/4*1/4*1/4=1/64
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