Ans: Given that, Bi=[0,i+1] , for each integer i=1,2,3,4.
Then for i=1, B1= [0, 1+1] =[0,2]
i=2, B2= [0, 2+1] =[0,3]
i=3, B3= [0, 3+1] =[0,4]
i=4, B4= [0, 4+1] =[0,5]
(a) Now we need to find B1B2B3B4
We know, x∈(A∪B) if and only if (x∈A) or (x∈B)
So, B1B2B3B4 = (((B1B2)B3)B4) = (([0,2][0,3])[0,4])[0,5])
=(([0,2,3][0,4])[0,5])
=([0,2,3,4][0,5])
=[0,2,3,4,5]
(b) Now we need to find B1B2B3B4
We know, x∈(AB) if and only if (x∈A) and (x∈B)
So, B1B2B3B4 = [0,2][0,3][0,4][0,5]
= [0] Since there is only one common point among all the four sets.
(c) We know,Disjoint set are those sets whose intersection with each other results in a null set.In other words, if F is a family of sets, the sets in F are mutually disjoint if and only if Ai ∩ Aj = ∅ for all Ai, Aj ∈ F and i j .
We can see from the above B1B2B3B4 = [0] ∅ .
Hence the sets Bi i=1,2,3,4 are not mutually disjoint.
Ans.
Let B;= [0,+ 1], for each integer i=1,2,3,4. Answer the following parts, showing all work. a)...
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