Question

Use the Kinematic Equations for Projectile Motion to answer the following problems. You will need to rearrange formulas to calculate the required parts. A baseball player makes a throw that travels 200 ft the CHLCULHTIONS through the air. The ball was in the air for 2.1 seconds. For this and similar problems, assume xo -and and yo -0. a. What was the horizontal velocity of the throw? Knowns (w/units) b. When was the ball at its maximum height? y- c. What was the maximum height of the throw? HINT: Use: y-gt+vyot yo Dyo 2. An Olympic long jumper leaps with an initial horizontalCILCULFTIONS velocity of 6 m/s and an initial ve cal velocity of 4.5 m/s. a. How long was the jumper in the air? Knowns (w/units) HINT: Use: vyyo t gt (how long did it take the jumper to reach the ground from her highest point?) yo b. What was the maximum height of the jump? c. How far was the jump? Pyo 21st Century Math Projects

Answer 1

x = x_0 + V_0x t x = 0 + V_0x t V_0x = x/t = 200 ft/2.1s = 95.238 ft/s V_0x = 95.238 ft/s V_0x = 95.238 ft/s = 29.3 m/s therefore V_ox = 29.03 m/s b) Time of flight T = 2.18a Time sof a cent Ta = 2.1/2 = 1.05sec (at maximum height) V_0x = V_0 cos theta = 29.03 m/s c) Times of flight T = 2 V^2_0y/g V_oy = squareroot Tg/2 = squareroot 2.1 times 9.8/2 V_0y = 3.21 m/s H_man = V^2_0y/2g = (3.21)^2/2 times 9.8 = 0.525m H_man = 0.525m H_man = 1.72ft a) T = 2V_0y/g = 2 times 4.5/9.8 = 9/9.8 = 0.918sec b) H_man = V^2_0y/2g = (4.5)^2/2 times 9.8 = 1.033m c x = V_0x T = 6 times 0.918 = 5.51m