Question

For project six, you will be given a list of MIPS machine language code instructions in memory. Your task is to Disassemble the contents and show the MIPS instructions. Make sure to calculate the correct branch target address for each branch instruction. If the resulting BTA happens to be outside the given code, this is OK, just make sure you calculate the BTA correctl Contents Address 0x00400024 Ox3c111001 0x00400028 Ox3410000a 0x0040002c Ox2a01000a 0x00400030 0x14200006 0x00400034 Ox8e280000 0x00400038 Ox01094820 0x0040003c Ox22100001 0x00400040 0x22310004 0x00400044 Ox0401fffa Solution Format: When writing your solution please use the following rules: 1. The REQUIRED file name is LastNameFirstName-p7.txt , where Last Name is your last name and FirstName is your first name 2. each line should be formatted in the following way address;contents;mips_instruction Please replace address, contents and mips instruction with their respective correct values 3. Each value on each line is REQUIRED to be separated by a semi-colon(;) . There should be nothing else inside the file, not even your name 5. There should only be 9 rows in your file. Anymore is breaking solution format 6. IF you wish to submt the work you did to get your answers, you may do so in a different file. This file can be named whatever you like

Answer 1

SOLUTION:

According to the given data the following CODE follows that illustrates the given data;

According to the following data the below instructions and contents,address follows as shown below;

Here the content with MIPS instruction and address that illustrates the data ;

Address	Contents	MIPS_Instructions
0x00400024	0x3c111001	LUI $s1,x1001
0x00400028	0x3410000a	ORI $s0, $zero ,10
0x0040002c	0x2a01000a	SLTI $1 ,$s0 ,10
loop1: 0x00400030	0x14200006	BNE 1t $zero loop
0x00400034	0x8e280000	LW $t0 0($s1)
0x00400038	0x01094820	ADD $t1 $t0 $t1
0x0040003c	0x22100001	ADDI $s0 $s0 1
0x00400040	0x22310004	ADDI $s1 $s1 4
0x00400044	0x0401fffa	BGEZ $zero loop1
loop:

àthe loop is considered or it means that the jump into the instruction in the address itself of "0x0040004c"

àthe loop is considered or it means that the jump into the instruction in the address itself of

"0x00400030”.

Therefore by using the above information we can get our required data