# of individuals marked in 1st catch - 50
# of individuals recaptured in 2nd catch - 5
Total # of 2nd catch - 40
N = (total # of 2nd catch) x (# of individuals marked in 1st catch) / # of individuals recaptured in 2nd catch
Therefore, N = 40*50/5 = 400
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Most rare - random dispersion
Most common - clumped dispersion
Associated with clumped resources - random dispersion
Associated with competition or territoriality - Uniform dispersion
A relatively uniform distribution - clumped dispersion
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2. SciSKILLS Calculate population size using mark-recapture data and understand the limitations of this technique What...
2. Let's try an example of the mark-and-recapture method. You would like to estimate the size of a population of wood frogs in a pond. You begin your sampling with a first capture of 22 individuals and you mark all of them. When you return, you capture 16 wood frogs and four of them are marked. In this example, a. M= b. C = c. R =
This experiment started with 50 snails. What was the calculated estimate of population size (N) for each of the samplings? How close were the calculations? Was the average of the two samplings close to the actual starting population size? Speculate why there was a difference between the estimated and actual values for the number of snails. Counting Snails: Ecological Sampling Technique 1st Recaptured Sample 2nd Recaptured Sample 108 112 Total Number Marked (M) 19 28 Number Recaptured with Mark (R) 86...
Please give the most simplest, easy to understand, short, straight to the point explanation. I'm struggling. Thanks in advance! (Please don't handwrite it) A. How do you use the mark recapture technique to estimate population size? B. What are the different types of competition? Is competition between species or individuals of the same species a positive species interaction or is it negative? C. What does fundamental niche mean? D. What does Realized niche mean? E. What does Müllerian mimicry mean?...
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