Why is the activity of Phosphofructokinase (PFK-1) high at moderate concentrations of ATP and low at high concentrations of ATP?
When there is a lot of ATP, it gets consumed more rapidly in other processes, which decreases the ability of PFK-1 to use it. |
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ATP is a competitive inhibitor of PFK-1. |
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At high concentrations ATP is an allosteric inhibitor of PFK-1. |
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ATP phosphorylates PFK-1, inactivating it. |
What is required for fermentation?
O2 |
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ATP |
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NADH |
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Pyruvate |
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Both NADH and pyruvate |
I. At high concentration, ATP molecule can bind at phosphofructokinase's regulatory site instead of binding to the active site of enzyme, which changes the shape of the enzyme in a way that results in dramatic fall in reaction rate at the active site. ATP acts as an allosteric inhibitor of PFK-1.
CORRECT OPTION IS " At high concentrations ATP is an allosteric inhibitor of PFK-1.
II. Both reduced NADH and pyruvate formed in glycolysis is required during fermentation. NADH reduces pyruvate and pyruvate is reduced into lactate (or ethanol).
CORRECT OPTION IS " Both NADH and pyruvate"
Why is the activity of Phosphofructokinase (PFK-1) high at moderate concentrations of ATP and low at...
QUESTION 1 Which of the following processes/pathways CANNOT occur in the absence of O2? Oxidative phosphorylation Substrate level phosphorylation Oxidation of NADH Photosynthesis Fermentation 1 points QUESTION 2 Phosphofructokinase (PFK-1) is one of the most regulated enzymes in metabolism. Which of the following would be expected to be an allosteric inhibitor of PFK-1? Glucose Fructose-6-phosphate Acetyl CoA AMP 1 points QUESTION 3 Which of the following is a reactant of the first reaction of glycolysis? Glucose ADP ATP...
The enzyme phosphofructokinase-1 (PFK-1) catalyzes the 3rd reaction in glycolysis. When AMP concentrations are very high, AMP binds to PFK-1, activating it. This is an example of: 1) competitive inhibition 2) allosteric activation 3) allosteric inhibition 4) direct feedback inhibition 5) end-product inhibition 6) both allosteric inhibition and end-product inhibition
Training Question 3. Shown below is the activity profile for the enzyme phosphofructokinase-1 (PFK-1) which catalyzes the reaction: Fructose 6-phosphate + ATP → fructose 1,6-biphosphate + ADP. Low (ATPI PFK-1 activity High (ATP) [Fructose 6-phosphatel Describe the different patterns of regulation for different ATP levels. Explain the why such regulation is appropriate for this enzyme, given its role in metabolism.
0.01 M A PFK-1 wity 2 mM ATT 02 M AMT -2 MATT 0 1.0 20 (RSP) MM According to the graph, which of the Vmax? According to the graph, which of the following best explains why curve C reaches AMP has a weak affinity for the regulatory site so ATP does not interfere with the reaction. ATP has a better affinity for the catalytic domain than the regulatory domain, thus binds in active site when concentrations of ATP are...
4. The X-fold increase in [AMP] (resulting from a 10% decrease in [ATP]) can be shown to be responsible for about a 9 told increase in flux through glycolysis by its action on phosphofructokinase alone. But a 9-fold increase is still not an -fold increase, so there must be something more to the story. That "something more" includes substrate cycling (see Figure 15-25 in your text). The reaction catalyzed by fructose-1,6-bisphosphatase (FBPase) acts as the reverse direction reaction for the...
Evce Monobran.UUUU 4. Phosphofructokinase is the rate-limiting enzyme that controls the rate on decreases its activity upon binding ATP. ATP concentrations mus y upon binding ATP. ATP concentrations must be relatively high for this to happen. This type of control of a biochemical pathway is called There are other ways to control the rate of biochemical pathways w ntrol the rate of biochemical pathways within cells. List three other typical ways cells would control rates of biochemical pathways. of relatie...
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Microbiology In the competitive inhibition of enzyme activity, which statement is correct? Inhibitor directly competes with the substrate. Less substrates must be added in order to reach Vmax. The number of active sites is unlimited. None of the above. In the noncompetitive inhibition of enzyme activity, which statement is correct?Inhibitors will cause a conformational change in the enzyme, more substrate must be added to reach Vmax, Enzymes bound to the inhibitor can still bind substrate, none of the above. ....
09. What goes into the Krebs cycle a. Acetyl c. Pyruvate Q9. What is made in Krebs cycle but not in glycolysis? . NADH b FADH C. ATP Q10. How is ventilation stimulated? a. Chemoreceptors detect low blood ph b. Chemoreceptors detect high blood pH Q11. Which of the following is an example of negative feedback? a. Low oxygen detected by peripheral chemoreceptors causes ventilation to increase b. High oxygen detected by peripheral chemoreceptors causes ventilation to increase 12. What...
1. According to the paper, what does lactate dehydrogenase (LDH) do and what does it allow to happen within the myofiber? (5 points) 2. According to the paper, what is the major disadvantage of relying on glycolysis during high-intensity exercise? (5 points) 3. Using Figure 1 in the paper, briefly describe the different sources of ATP production at 50% versus 90% AND explain whether you believe this depiction of ATP production applies to a Type IIX myofiber in a human....