Question

A 35.0 g horizontal metal bar, 8.50 cm long, is free to slide up and down along two tall, vertical metal rods that are 8.50 cm apart. A 0.250  resistor is connected across the two rods at the top and a 0.600 T magnetic field is directed perpendicular to the plane of the rods (out of the page). The metal bar is raised to the top of the rods and then released. Assume that the bar remains horizontal and in contact with the vertical rods as it falls. a) Draw a sketch illustrating what is going on. b) In which direction is the current induced in the bar? Explain. c) In which direction is the magnetic force on the bar? Explain. d) What is the terminal speed at which the bar falls?

Answer 1

7 -0.25 0 0 0 0 0 Male o bar, m=35g its g. 50cm Resistance, R=0.252 Magnetic field, B=0.6007 of 6 As the rod falls down - Force on charge particle is towards egz left so current will flow in clockrouse direction as shown to → we can also say that the fulx crossing the rod increases so to Oppoge the change using lenz's laro a current will be induced in elouchouse direction. © Magnetic force, FB = 3 XB tuc h = {{DXB) (-2x RJ T = IIB . This direction of magnetic force is towards upward opposite to gravitational once. @ For terminal velocity rod will un equilibrium - FB = Fg Il Bang Now I = Eynd (Bly) => BOLA mg > Ut ng R = 0.035X9.8X0.25 mk > 4= 32.97 m/s 00602 x (@_085j2 or, vt ~Bloomis