Question

the Poc ca when near cons lane

Answer 1

Given, x(n) = (y_2)^n u(n) + 2^n u(- n - 1) y(n) = 6(y_2)^n u(n) - 6(3/4)^n u(n) we have standards z transforms as, z{a^n u(n)} = z/z - a: z{ - a^n u(- n - 1)} = z/z - a (i) So, to find transfer function, H(z) = y(z)/x(z)_(1) H(z) = -3z - 12z/(2z - 1)(4z - 3)/- 3z/(2z - 1)(z - 2) H(z) = 4z - 8/4z - 3 x(z) = z/z - y_2 - z/z - 2 = 2z/(2z - 1) - z/z - 2 rightarrow - 3z/(2z - 1)(z - 2)_(1) y(z) = 6 z/z - y_2 - 6 z/z - 3/4 rightarrow 6[2z/2z - 1 - 4z/4z - 3] rightarrow 6[- 2z/(2z - 1)(4z - 3)]

I hope you understand above solution. If any doubts, do comment below.