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In order to prepare your KIO3solution for titration, you pipet 10.00 mL of a 0.2732 N...

In order to prepare your KIO3solution for titration, you pipet 10.00 mL of a 0.2732 N KIO3stock solution and dilute it to the mark using a 250-mL volumetric flask. What is the concentration of the resulting KIO3solution that you will use in the experiment?

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Answer #1

As N1*V1 = N2*V2

where N1 and N2 are the concentrations (normalities) of solutions 1 and 2 respectively

And V1 and V2 are the volumes of solutions 1 and 2 respectively

Now , N1 = 0.2732N , N2 = ? , V1 = 10 ml , V2 = 250 ml , therefore ,

0.2732 * 10 = N2*250

N2 = (0.2732*10)/250 = 0.0109 N

So, concentration (normality) of resulting KIO3 solution after dilution is 0.0109 N .

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