The current in a 6.0 V device is 0.15 mA. In half an hour of operation, C of charge flows in the circuit and J of energy is delivered to the circuit.
Solution :
Given :
V = 6 V
I = 0.15 mA = 150 A
and, time (t) = half an hour = 30 min = 1800 sec
Since : I = Q / t
Thus : Q = I t = (150 A)(1800 sec) = 270000 C = 2.7 x 105 C
And, Energy = V I t = (6 V)(150 A)(1800 s) = 1.62 x 106 J
Therefore:
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