A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there...
A Xw+m+Xwm female was mated to a XwmY male. Out of 1000 total F1 progeny there were 230 flies that were otherwise wild type with white eyes and 240 flies that were otherwise wild type with miniature wings. What is the distance between the genes for eye color and wing length?
A. 47 map units
B. 24 map units
C. 53 map units
D. 23 map units
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A Xw+m+Xwm female was mated to a
XwmY male. Out of 1000 total F1 progeny there...
A female fruit fly with vermilion eyes and normal wings is crossed to a male with...
A female fruit fly with vermilion eyes and normal wings is crossed to a male with normal red eyes and cut wings. The F1 progeny consist of females with red eyes and normal wings, and males with vermilion eyes and normal wings. When the F1 progeny are interbred, the F2 consists of two types of females vermilion eyes, normal wings (1/2) and red eyes, normal wings (12), and two types of males-vermilion eyes, normal wings (12) and red eyes, cut...
The results for the F2 progeny are shown for a F1 cross using the two X-linked...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
Mutant Female x Wild Type Male Wild Type Wing & Red Eyes Females 121 Mutant Wing...
Mutant Female x Wild Type Male Wild Type Wing & Red Eyes Females 121 Mutant Wing & White Eyes Males 95 Wild Type Female x Mutate Male Wild Type Wing & Red Eyes Females 43 Wild Type Wing & Red Eyes Males 45 Blue Label Red Label F1 Female x Mutant Male F1 Female x Mutant Male Wild Type Wing & Red Eyes Female 91 Wild Type Wing & Red Eyes Female 42 Wild Type Wing & Red Eyes Males...
could someone help me figure out how to do these pleaseeee A female fruit fly who...
could someone help me figure out how to do these
pleaseeee
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A white eyes female fruit fly is mated to a red eyed (wild type) male. While...
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Drosophilia homozygous for the lobed eye mutation (L) were mated with flies homozygous for a wing...
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Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed...
Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed male. The Fl generation all have normal wings and red eyes. The FI offspring are crossed with miniature-winged, vermillion-eyes flies. The following offspring of that cross were counted. 233 normal wing, red eye 247 miniature wing, vermilion eye 7 normal wing, vermilion eye 13 miniature, red eye a) Explain what a testcross is (1 point). b) What is the expected phenotypic ratio from a...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated with a female from a true-breeding stock with normal eyes and javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normal eyes and normal bristles. F1 females from this cross were mated with males with both scabrous eyes and javelin bristles. a. Write all the possible phenotypic classes of the progeny that could be produced...
2. A truebreeding female Drosophila with little wings (lw/lw) and red eyes (pr+/pr+) was crossed to...
2. A truebreeding female Drosophila with little wings (lw/lw) and red eyes (pr+/pr+) was crossed to a male with normal wings (lw+/lw+) and purple eyes (pr/pr). All of the F1 appeared wild type. A testcross was done with an F1 female and a tester male. The following data was from the testcross. Fill in the table below. (4) a. generated Phenotype of Genotype of Parental or recombinant? # observed testcross progeny progeny Little wings and purple eyes 51 Normal wings...
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"Ebony body, held-out wings and sepia eyes are ALL RECESSIVE AND ALL ON CHROMOSOME 3. The COEFFICIENT of COINCIDENCE for chromosome 3 is 0.5. A homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. The F1 are wild-type. An F1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. If ebony and held-out are separated by 12 map units, and held-out and sepia...
A female fruit fly with vermilion eyes and normal wings is crossed to a male with normal red eyes and cut wings. The F1 progeny consist of females with red eyes and normal wings, and males with vermilion eyes and normal wings. When the F1 progeny are interbred, the F2 consists of two types of females vermilion eyes, normal wings (1/2) and red eyes, normal wings (12), and two types of males-vermilion eyes, normal wings (12) and red eyes, cut...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
could someone help me figure out how to do these
pleaseeee
A female fruit fly who is heterozygous with the phenotype gray body, red eyes & long wings is crossed with a male who is homozygous recessive (black body, purple eyes, vestigial wings). The observed offspring are shown below: # offspring, body color. eye color. wing length 411 gray red long 61 gray red vestigial 2 gray purple long 30 gray purple vestigial 28 black red long black red vestigial...
Drosophilia homozygous for the lobed eye mutation (L) were mated with flies homozygous for a wing mutation known as plexus (px) All the f1 progeny had lobed eyes and wild type wings. The F1 flies were test crossed resulting in the following progeny: Number 18 F2 phenotypes Wild type eyes and wings Lobed eyes Plexus wings Lobed eyes and plexus wings 35 33 14 Write the genotypes of the parental and f1 flies. Use proper drosophilia nomenclature. Be sure to...
Question 3 Two true-breeding Drosophila are crossed: a normal-winged, red-eyed female and a miniature- winged, vermillion-eyed male. The Fl generation all have normal wings and red eyes. The FI offspring are crossed with miniature-winged, vermillion-eyes flies. The following offspring of that cross were counted. 233 normal wing, red eye 247 miniature wing, vermilion eye 7 normal wing, vermilion eye 13 miniature, red eye a) Explain what a testcross is (1 point). b) What is the expected phenotypic ratio from a...
(1) A Drosophila male from a true-breeding stock with scabrous eyes and normal bristles was mated with a female from a true-breeding stock with normal eyes and javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normal eyes and normal bristles. F1 females from this cross were mated with males with both scabrous eyes and javelin bristles. a. Write all the possible phenotypic classes of the progeny that could be produced...
2. A truebreeding female Drosophila with little wings (lw/lw) and red eyes (pr+/pr+) was crossed to a male with normal wings (lw+/lw+) and purple eyes (pr/pr). All of the F1 appeared wild type. A testcross was done with an F1 female and a tester male. The following data was from the testcross. Fill in the table below. (4) a. generated Phenotype of Genotype of Parental or recombinant? # observed testcross progeny progeny Little wings and purple eyes 51 Normal wings...
"Ebony body, held-out wings and sepia eyes are ALL RECESSIVE AND ALL ON CHROMOSOME 3. The COEFFICIENT of COINCIDENCE for chromosome 3 is 0.5. A homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. The F1 are wild-type. An F1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. If ebony and held-out are separated by 12 map units, and held-out and sepia...
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