Homework Answers
Answer:
2. It shows an initial inoculation phase that is ,initial lag phase.
3. No dead cells donot contribute to OD. OD decreases when the cell enters the death phase of the culture.
4.OD600 measurements is useful as the cells donot gets killed at this wavelengths of light as compared to other UV light spectrometers .
To prevent undesirable mutations in the bacterial cultures
To differentiate from the culture broth colours which tends to be yellow sometimes
So OD with higher wavelengths in the visible range used.
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2. If the OD600 of a culture is 0.4, what phase of growth is the culture...
please use these results of a growth curve experiment to answer the following questions Questions 1)...
please use these results of a growth curve experiment to
answer the following questions
Questions 1) Plot the OD600 readings and cell concentration for each time point on a scatterplot with a line connecting the points. Have the measured data (OD600 and cell concentration) on the y-axis against the time on the x-axis using Excel (or other computer based data/graphing program). It is helpful to set the y-axis on a log scale for the cell concentration measurements. 2) Can you...
this is a bacterial growth curve experiment . please explain rhe results Procedure: You will follow...
this is a bacterial growth curve experiment . please explain
rhe results
Procedure: You will follow the growth of E. coli over the course of the period (3 hrs) by making direct counts of the bacterial suspension by measuring the turbidity of a sample at a given time with a spectrophotometer. The data obtained from the direct counts will be used to plot a partial growth curve. Summary: Turbidity Counts with the Spectrophotometer to measure absorbance at 600. Direct Counts...
How do I calculate the number of cells recovered in a suspension? What information do I...
How do I calculate the number of cells recovered in a suspension? What information do I need? Also, calculate the percent increase in cell density from the time of IPTG addition to the time when the cells were harvested. The OD of the E.coli culture is around OD 2-2.5. 10ml of culture was added to each flask. Components IPTG (+) OD600 IPTG(-) OD600 E.coli+Glucose+Ampicillin 0.6263 0.5764 E.coli+Glucose+Ampicillin after IPTG and growth 0.2870 0.2041
3) Use the logarithmic phase of the growth curve to estimate the generation time (g units...
3) Use the logarithmic phase of the growth curve to estimate the generation time (g units are hours/generation; also known as the doubling time) of E. coli. How does the generation time that you estimated compare to the published generation times for E. coli growing under optimal conditions? What are some of the possible reasons for differences in the generation times? What are possible sources of error in this exercise? OD600 readings and cell concentration OD600 Readings Cell Concentration (cell/mL)...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times an...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times and dilute them in 10-fold series (as shown in the 2 row of the table) and plate 0.1 ml of each of these dilutions on five standard lab agar plates. The average number of colonies per plate are below Time of Colonies on plate at each dilution ars 45 290 TNTC TNTC 195 20 TNTC TNTC 200 TNTC too numerous to count ADB MO...
What would be some reasons as to why a bacterial growth curve would produce unexpected results?...
What would be some reasons as to why a bacterial growth curve
would produce unexpected results? For example, an E. coli culture
increases after the stationary phase? Or why there is no
stationary phase? I am trying to
interpret results that I have from a lab experiment.
Viable Cell Concentration vs. Time of Escherichia coli E 1.00E+08 1.00E-07 C 1.00E+06 60 80 100 120 140 0 20 40 Time (minutes) Spectrophotometer -96 Well Plate
17.A viable count of this culture, which represents Staphylococcus aureus, was done after 120 minutes. How...
17.A viable count of this culture, which represents Staphylococcus aureus, was done after 120 minutes. How many CFUs are expected if you plated 0.2 mL of a 104 dilution? (Hint: Consider the average number of cells per CFU) 18. At 65 minutes, the cells were transferred to a new medium in which the growth rate (H) was three times lower. What is the expected number of cells after 60 minutes of growth following the transfer? 19.By what factor did the...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times and dilute them in 10-fold series (as shown in the 2 row of the table) and plate 0.1 ml of each of these dilutions on five standard lab agar plates. The average number of colonies per plate are below Time of Colonies on plate at each dilution ars 45 290 TNTC TNTC 195 20 TNTC TNTC 200 TNTC too numerous to count ADB MO...
The adaptation phase for the E. coli culture lasted A culture of E. coli was grown...
The adaptation phase for the E. coli culture lasted
A culture of E. coli was grown on suitable culture media; aliquots of the culture were serially diluted and spread plated aseptically on agar plate media at the times indicated in the table below. Upon overnight incubation at 37°C, colonies appeared and viable counts were colleted and displayed below. Hours 0 Viable Counts (CFU/mL) 2 .00 x 107 2.10 x 107 2.30 x 107 3.25 x 107 6.60 x 107 1.40...
Observation of a streak-plate culture show more growth in quadrant #4 than in quadrant #3. What...
Observation of a streak-plate culture show more growth in quadrant #4 than in quadrant #3. What could account for this observation? loop was properly sterilized after every single streak ОА. student got distracted and as they were streaking quadrant 14, they crossed through quadrant OB some bacteria show increased motility and travel faster from one quadrant to another ос. the growth rate of bacteria increased as it was incubated at 37°C OD
please use these results of a growth curve experiment to
answer the following questions
Questions 1) Plot the OD600 readings and cell concentration for each time point on a scatterplot with a line connecting the points. Have the measured data (OD600 and cell concentration) on the y-axis against the time on the x-axis using Excel (or other computer based data/graphing program). It is helpful to set the y-axis on a log scale for the cell concentration measurements. 2) Can you...
this is a bacterial growth curve experiment . please explain
rhe results
Procedure: You will follow the growth of E. coli over the course of the period (3 hrs) by making direct counts of the bacterial suspension by measuring the turbidity of a sample at a given time with a spectrophotometer. The data obtained from the direct counts will be used to plot a partial growth curve. Summary: Turbidity Counts with the Spectrophotometer to measure absorbance at 600. Direct Counts...
3) Use the logarithmic phase of the growth curve to estimate the generation time (g units are hours/generation; also known as the doubling time) of E. coli. How does the generation time that you estimated compare to the published generation times for E. coli growing under optimal conditions? What are some of the possible reasons for differences in the generation times? What are possible sources of error in this exercise? OD600 readings and cell concentration OD600 Readings Cell Concentration (cell/mL)...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times and dilute them in 10-fold series (as shown in the 2 row of the table) and plate 0.1 ml of each of these dilutions on five standard lab agar plates. The average number of colonies per plate are below Time of Colonies on plate at each dilution ars 45 290 TNTC TNTC 195 20 TNTC TNTC 200 TNTC too numerous to count ADB MO...
What would be some reasons as to why a bacterial growth curve
would produce unexpected results? For example, an E. coli culture
increases after the stationary phase? Or why there is no
stationary phase? I am trying to
interpret results that I have from a lab experiment.
Viable Cell Concentration vs. Time of Escherichia coli E 1.00E+08 1.00E-07 C 1.00E+06 60 80 100 120 140 0 20 40 Time (minutes) Spectrophotometer -96 Well Plate
17.A viable count of this culture, which represents Staphylococcus aureus, was done after 120 minutes. How many CFUs are expected if you plated 0.2 mL of a 104 dilution? (Hint: Consider the average number of cells per CFU) 18. At 65 minutes, the cells were transferred to a new medium in which the growth rate (H) was three times lower. What is the expected number of cells after 60 minutes of growth following the transfer? 19.By what factor did the...
3. You are measuring the growth of bacterium using cfu mL·You collect samples at various times and dilute them in 10-fold series (as shown in the 2 row of the table) and plate 0.1 ml of each of these dilutions on five standard lab agar plates. The average number of colonies per plate are below Time of Colonies on plate at each dilution ars 45 290 TNTC TNTC 195 20 TNTC TNTC 200 TNTC too numerous to count ADB MO...
The adaptation phase for the E. coli culture lasted
A culture of E. coli was grown on suitable culture media; aliquots of the culture were serially diluted and spread plated aseptically on agar plate media at the times indicated in the table below. Upon overnight incubation at 37°C, colonies appeared and viable counts were colleted and displayed below. Hours 0 Viable Counts (CFU/mL) 2 .00 x 107 2.10 x 107 2.30 x 107 3.25 x 107 6.60 x 107 1.40...
Observation of a streak-plate culture show more growth in quadrant #4 than in quadrant #3. What could account for this observation? loop was properly sterilized after every single streak ОА. student got distracted and as they were streaking quadrant 14, they crossed through quadrant OB some bacteria show increased motility and travel faster from one quadrant to another ос. the growth rate of bacteria increased as it was incubated at 37°C OD
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