Question

9.36 In a nuclear power plant the reactor transfers the heat to a flow of liquid sodium, which in a heat exchanger transfers the heat to boiling water. Saturated vapor steam at 5 MPa exits this heat exchanger and is then superheated to 600°C in an external gas-fired superheater. The steam enters the turbine, which has an extraction at 0.4 MPa to an open FWH, and the condenser pressure is 10 kPa. Determine the heat transfer in the reactor and in the superheater to produce a net power output of 5 MW.

Answer 1

5MPq yinen that 0.414Pa lokpa tmo.4 MPa harz k hez (lokPa] OFWH At, diumpa, hq = 2737.6 Kglig Ther= 604.7kJ/kg At 10kPa hfz = 19108 kg / kg From Energy Balance mihat pam) haza hifa ma by ho 6.4.17-1918 the Yoga = 2737.6 - 191.18 m = 0.162kg | AH SMPA, prig of the 2787.44 koling Mow 5MPa, Good, th, 23666.02 kJ/kg keat transfer in Paltor antho-hea) = 6.162 (2487.44 - 604.49 QR = 253.60 kJ Heat trauffer in Superteaty QS=mPhonho] = 0.162 [3666.02-27843 as = 142.40 KJ) @R)

First of all ,we find mass

By energy balance in open feed water heater,

So we get m(Kg)

Heat transfer in reactor Qr= m(h8-hf2)

Hear transfer in superheater Qs= m(h1-h8)