Question

Part 1

A simple epicyclic gear has a sun gear with 10 teeth and a ring gear with 100 teeth. If the sun gear is held stationary, calculate the speed/gear ratio when the ring gear is the input and the planet carrier is the output?

Part 2

Two parallel shafts which are 220mm apart are to be connected by a simple gear train, will all gear centres on the same line, using gears from a pool of six gears of teeth numbers 120, 80,60,40,20 and 10, all having the same module of 4mm. If the desired gear ratio is to be +6 which gears can be used?

Answer 1

Part - I number of teeth on sun gear t = 10 number of teeth on ring gear T = 100 sun gear is stationary find the tabular method Sun gear (A) is stationary x + y = 0 x = -y calculate the speed ratio = speed of driver (input)/speed of follower (output) \r\n speed ratio = speed of ring gear/speed of carrier (Arm) = y - x/10/y = y - y/10/10 (because x = -y) speed ratio = 1+ 1/10 = 11/10 speed ration = 1.1 part 2 given data: - distance between the shaft is 220 mm, no of teeth T_1 = 120 , T_2 = 80 T_3 = 60 , T_ g = 40 , T_5 = 20 , T_6 = 10 module m = 4. gear ratio = 6 \r\n calculate the diameter of all gears d_1 = m T_1 = 4 times