Q(present state) | D(input) | Q+(next state) |
---|---|---|
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 0 |
1 | 1 | 1 |
Q(present state) | T(input) | Q+(next state) |
---|---|---|
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 0 |
Q(present state) | J | K | Q(next state) |
---|---|---|---|
0 | 0 | 0 | 0 |
0 | 0 | 1 | 0 |
0 | 1 | 0 | 1 |
0 | 1 | 1 | 1 |
1 | 0 | 0 | 1 |
1 | 0 | 1 | 0 |
1 | 1 | 0 | 1 |
1 | 1 | 1 | 0 |
Q(present state) | jk | Q(next state) |
---|---|---|
0 | 0X | 0 |
0 | 1X | 1 |
1 | X0 | 1 |
1 | X1 | 0 |
BASED ON ABOVE TRUTH TABLES
QA | QB | QC | JAKA | TB | DC | QA+ | QB+ | QC+ |
---|---|---|---|---|---|---|---|---|
0 | 0 | 0 | 0X | 1 | 0 | 0 | 1 | 0 |
0 | 0 | 1 | 1X | 0 | 1 | 1 | 0 | 1 |
0 | 1 | 0 | 1X | 1 | 0 | 1 | 0 | 0 |
0 | 1 | 1 | 0X | 0 | 1 | 0 | 1 | 1 |
1 | 0 | 0 | X1 | 0 | 1 | 0 | 0 | 1 |
1 | 0 | 1 | X0 | 1 | 0 | 1 | 1 | 0 |
1 | 1 | 0 | X0 | 0 | 1 | 1 | 1 | 1 |
1 | 1 | 1 | X1 | 1 | 1 | 0 | 0 | 1 |
In the above table Q+ respresnt next state
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please show your work Complete the following state table. Note that the flip-flops are not all...
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Complete the following state table. Note that the flip-flops are not all of the same type. Present FFin Next QA QB Qc JAKA DB QA Qв Qс 0 о 0 0 0 0 0 0 1 1 1 o 1 0 0 0 0 0 1 1 1 1 0 1 0 0 1 10 10 1 0 0 0 1 1 0 0 1 1 1 1 1 1 10
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Fill in the state table for the following state diagram. Clearly label each column with its usage (Present. Input, Output, Next). Use only as many rows as needed. 1 00 0 0 ( 11 QB 10 QA QB
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4. Design a sequential circuit using D flip-flops that produces the following state table: 1 Present Next QU Q.Qo Qu Q.Qo 0 00 XX 0 01 00 0 10 01 0 11 0 10 00 01 01 10 10 0 11 11 X XX 1 1 1 There are three bits of state split into a single bit Qu and an unsigned two-bit number Q1 Qo. You may assume that the counter does not start in...
ECE 204 Pre-Lab 12 Flip-flops [11 next output for Q when counting up, with QA being least significant bit (LSB) and Qg being most significant bi (MSB) Fill out the truth table below with Q+ being the QQQQ+ 0 0 0 I To implement this using D flip flops, the D input (data) is written to Q when the clock gets to the next cycle, so that means that the D input needs the Q+ during the clock event, or...
Design a BCD counter with four T flip-flops. - The state table should have the present state, next state, output, minterm, and flip-flop inputs. The output signal Y = 0 only during the counter transition from 1001 to 0000, otherwise, Y = 1 (for each valid input). - The input equation for TQ4, TQ2 and TQ1 in SOP. - The equation of the output signal Y in SOP.
Implement the following logic table using JK flip-flops. 01 and Q0 represent the current state, X represents the machine's input, D1 and DO represent the next state, and Z is a machine output. 3) Q1 Q0 X D1DOZ 0 0 1 0 0110 0 0 0 0 0 0 0 0 0 Repeat problem 3), except implement the machine as a "one-hot" state machine. Label your flip flops "ОО", "O1", "10", and "11". 4)
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JK Flip-Flop S R Flip-Flop From(Q) To (Q+) S 0 0 R T Flip-Flop From(Q) To(Q+) 0 0 JK From(Q 0 To (Q+) 0 -- - c) Complete the timing diagram below. Assume that both of flip-flops are edge triggered. (10 pts) Clock
Design a BCD counter that uses four(4) T flip-flops using the given table format below. The output signal Y = 0 only during the counter transition from 1001 to 0000, otherwise, Y = 1 (for each valid input). Determine the following: (a) The circuit's state table Present State Next State Output Minterm Flip-Flop Inputs Q. Q4 Q1 Q: Q4 Q2 Q1 Y (m) T24 T02 TQ1 T08 Required format of the state table in Problem 2(a). Show table grid lines...
Use S-R flip-flops to design a 3-bit counter (C, B, A) with the repeating binary counting sequence: 1, 3, 2, 6, 7, 5, 4. Show clearly the following: (a) The circuit's state table with the present-state entries in ascending order. Present State (t) Next State (t+1) Flip-flop Inputs с B A m с B A Sc Rc SB RE SA RA Required format of the state table in Problem 1(a). Show table grid lines and align all entries per column....
Derive the state diagram, state table, state assignment table, and logic network using D flip-flops for the following circuit: A FSM has two input, w1 and w2, and an output z. The machine has to generate z=1 when the previous four values of w1 and w2 are the same; otherwise z=0. Overlapping patterns are allowed. An example of the desired behavior is: w1: 0 1 1 0 1 1 1 0 0 0 1 1 0 w2: 1 1 1...