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Question 4 4 pts Use the Born-Haber Cycle to calculate the lattice energy for the formation...
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
OADVANCED MATERIAL Interpreting a Born-Haber cycle This thermodynamic cycle describes the formation of an ionic compound M X2 from a metal element M and nonmetal element X in their standard states. Use it to answer the questions in the table below. 2+ 1100 1000 900 2- 800--- 700 600 M (8)+2X) 500. enthalpy 400 (kJ/mol) 300. M (g) + X, (g) 200 ▼ | 700,- 600 M (g) + 2x (g 500 enthalpy 400. 300. м (е) + x, (g)...
4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided table. (Show all your work; 2 points) Enthalpies, AH/(kJ mol) +192 Process Sublimation of Ca(s) Ionization of Ca(g) Dissociation of F2(g) Electron gain by F(g) Formation of CaF (s) +1735 to Ca(ag +157 -328 -1220
Draw the Born-Haber Cycle with these values and calculate lattice energy. Problem 1: Label each reaction listed below for the Born-Haber cycle in the formation of Cao lattice and calculate the lattice energy of Cal given the following information. AH KD) Ca(s) + Ca(8) 193 Calg) - Cat (8) + e 590 Cat (8) - Cat (8) + e- 2 O(g) + O2(g) O(8) + e- O (8) -141 O (8) + e- O (8) 878 Ca(s) + O2(g) →...
Use the Born Haber cycle (see equations and enthalpy values below) to determine the lattice energy for BeI2 (s) (∆H LE (BeI2 (s))= ?) Show your work. Box your final answer. A. Be(g)→Be1+ (g) + 1 e–∆H = + 899.5kJ B. Be1+ (g) →Be2+ (g) + 1 e–∆H = +1757 kJ C. Be(s)→Be(g)∆H= +302kJ D. I2(s)→I2(g)∆H= + 62.4kJ E. I(g) + e–→I–(g)∆H= –295kJ F. I2(g)→2I(g)∆H= + 151 kJ G. Be(s) + I2(s) →BeI2(s)∆H= –208 kJ
Part I. Use a Born-Haber cycle to calculate the lattice energy of KCl from the following data. (5 marks) Ionization energy of K(g) = 444.0 kJ mol-1 Electron Affinity of Cl(g) = -381.0 kJ mol-1 Energy to Sublime K(s) = 152.0 kJ mol-1 Bond energy of Cl2 = 201.0 kJ mol-1 ∆rH for K(s) + 1/2 Cl2(g) ↔ KCl(s) = -480.0 kJ mol-1 art II. Using the lattice energy calculated in part I determine the enthalpy of solution potassium chloride...
Physical Chemistry: Use a Born-Haber cycle to find an experimentally based value for the lattice enthalpy of sodium bromide (NaBr(s)). The lattice enthalpy corresponds to the enthalpy change for the process NaBr(s) rightarrow Na^+(g) + Br^-(g) Use the following information in doing this problem. delta H degree_f(Na(g)) = 107.32 kJ/mol delta H degree_IE1(Na(g)) = 495.8 kJ/mol delta H degree_f(Br(g)) = 111.88 kJ/mol delta H degree_EA(Br(g)) = -324.6 kJ/mol delta H degree_f(NaBr(s)) = -361.06 kJ/mol The ionization enthalpy (IE_1) and electron...
Using the Born-Haber cycle shown below, calculate the lattice energy for MgCl2 in kJ* mol-1 Mg**g) + 2Cl(g) 2 x-349 AH2nd le(Mg) - 1451 2xAH (01) --698 My*(g) 2013) Mg (g) + 2Cl(g) AHORE (Mg) - 738 Mg(g) + 2Cl(g) 2 x 122 2xAH CIT- +244 Mg(g) + Cl2(g) AHTE (MgCl2) Mg(s) + Clą(9) AHM9) - 148 AH, (MgCl2) --641 MgCl (s)
Use the Born-Haber Cycle and information given below to determine the lattice energy of LiF. Li(s) → Li(g) +159.3 kJ Li(g) → Li+(g) + e– +500.9 kJ F2(g) → 2 F(g) +158.8 kJ F(g) + e– → F–(g) –332.6 kJ Li+(g) + F–(g) → LiF(s) ? --------------------------------------------------- Li(s) + ½ F2(g) → LiF(s) – 616.0 kJ Group of answer choices +209.0 kJ –1023 kJ +1023 kJ –209.0 kJ –1102.4 kJ
Discuss the relationship of calculating lattice energy and the Born-Haber cycle. Here are some suggestions of topics on which to elaborate upon in your explanations: Provide an explanation of the Born-Haber cycle. Explain the difference between ionization energy and electron affinity. Explain how the enthaply of formation is related to the Born-Haber cycle.