Question

QUESTION 23 In this figure, the numbers 1-6 represent reactants/products, and the letters A-E represent enzymes for the reactions. Select the most appropriate statement. Product Reactant Product It is most efficient for product 6 to Inhibit enzyme A. It is most efficient for product 3 to Inhibit 4 It is most efficient for product 6 to Inhibit enzyme c It is most efficient for product 3 to Inhibit 2. QUESTION 24 During catabolism, several high energy molecules are generated. Which of the following molecules does not belong to the category of high energy molecules? FADH2 ATP NADH COA QUESTION 25 If a fatty acid has a symbolic name 18:3 n-3 then the statement which would not correspond to the properties of this fatty acid is The position of the first double bond is between carbons 3 and 4 The length of the carbon chain is 18 There are 3 double bonds The position of the last double bond is between carbon 15 and 16

Answer 1

represent fatty acide Ans (23) The Correct answer for this question is — d> The position of the last double bonel is between Carbon 15 and 16. Explanation go this questions 18:3 n.3 unsaturated * The muning of this ier 18 : 3 L Double boned after 18 number 13rd carbon atom . vices between 3 Carbon atom and 4 carbon atom y Hence Obtion and @ Correct statement but in not represent double bond between Carbon 15 and 16. Hence the correct option 7-3 13. double bond is a mo is - dy Ans. A0 ا ر b) VAU 20 The correct 90swer for this questions is a) U AUTUAC Exblossation- The mutation in all 4 option show both code for Pyrosine and UAC a) U AU UAC hence this is same sense mutation. → UAA, Tyrosine to stole Creon meen it terminate translation hence it is non-sense mortation. e) UAU → UAG, Tyrosine to stole codon meens it terminate translation hence it is non-sense mutation. d) AAG AGIG, Lysine to Arginine soes change in Amino Acid hence it is mis. sense mutation Conclusion since when it mutate UAU to UAE in amino acid occur o no change Uits sense mutation heree it will be least lethal Same

Ans. 23) The correct answer for this question is- ay gt is most efficient for product 6 to inhibit enzyme A. xiplomation Bis is multi step reaction. А 118 3 u Regarding the inhibition the best answer will be end broduct jie, inhibit starting enzyme - ④ if concentration increase hence feed back inhibition. it will be most effective. Hence Enzyme inhibited by end product. conclusion - Hence from above discussion end brocluct inhibition of storting enzyme-A is most abboniate statement hence is option-A. Ans. 24 The correct for this question is ely CoA. Explanation gn catabolism usually energy release like Carbohydo. break in to complete co then release energy, & Energy is of two tybe. answer GOs wer Direct source. Indirect y used in their own. y convert in to App. ex-APP ex- FADH2 and NADH, JFADH₂ form 2 ATP while NADH form 3 ATP. y while coA is intermediate substance not high energy substance Conclusion - Hence correct is d) Con (coenzyme-A), answer