Homework Answers
The correct option b. (Two bands one formed using only N14 and one formed by N15).
During conservative mode of DNA replication, Two daughter strands synthesized from two template DNA strand of parent DNA, are coiled together. Therefore, if the parent strand has N15 and replicate through conservative mode in a medium containing N14, the resulting daughter strands with N14 will coil together as one double helix. Hence, the parent strands will have N15 and daughter strands will have N14. After 3 rounds of conservative DNA replication, 7 out of 8 DNA double helix will have N14 and only one starting parent strand will have N15. Hence, after centrifugation two bands will be observed : one band of N15 and another band of N14.
Option a is incorrect: As there will be only two types of DNA molecule : N15 and N14, not more than two types of bands will be observed. Hence, this option is incorrect.
Option c is incorrect: Centrifugation can easily determine the types of bands and mode of replication. Hence, this option is incorrect.
Option d and e are incorrect: Hybrid bands (N15: N14) will not be seen in case of conservative replication, as the parent strand remain conserve and daughter strand consists of newly formed DNA. Hence, these options are incorrect.
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If DNA was replicated via a conservative mechanism and you repeated the Meselson and Stahl experiment,...
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In the classic paper that demonstrated the semi-conservative replication of DNA, Meselson and Stahl began by...
In the classic paper that demonstrated the semi-conservative
replication of DNA, Meselson and Stahl began by showing that DNA
itself will form a band when subjected to equilibrium
sedimentation. They mixed randomly fragmented E coli DNA with a
solution of CsCl so that the final solution had a density of 1.71
g/ml. As shortn in Figure Q8-2, with increasing length of
centrifugation at 70,000 times gravity, the DNA, which was
initially dispersed throughout the centrifuge tube, became
concentrated over time...
Please explain which one I missed, I got a 8/10. Might be the last question that...
Please explain which one I missed, I got a 8/10. Might be the
last question that I missed!
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In the late 1950s, Meselson and Stahl grew bacteria in a medium containing "heavy" nitrogen (^15 N) and then transferred the bacteria to a medium containing^14 N ("lighter" nitrogen) and allowed some of the the bacteria to undergo one round of replication and some bacteria to undergo two rounds of replication. They then performed density gradient centrifugation and looked to see where the DNA settled in the test tube. In the diagram below, draw bands indicating the density of the...
In the classic paper that demonstrated the semi-conservative
replication of DNA, Meselson and Stahl began by showing that DNA
itself will form a band when subjected to equilibrium
sedimentation. They mixed randomly fragmented E coli DNA with a
solution of CsCl so that the final solution had a density of 1.71
g/ml. As shortn in Figure Q8-2, with increasing length of
centrifugation at 70,000 times gravity, the DNA, which was
initially dispersed throughout the centrifuge tube, became
concentrated over time...
Please explain which one I missed, I got a 8/10. Might be the
last question that I missed!
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