Question

Please read the following prompt carefully: "A Tootsie Pop is a lollipop with a chocolate center. A famous commercial asked, 'How many licks to the center of a Tootsie Pop?' A study found that the number of licks required before reaching the chocolate center of a Tootsie Pop is 364. In disbelief, a competitor asked 30 randomly selected individuals to count the number of licks required before reaching the chocolate center. The mean number of licks required was 346 with a standard deviation of 176. Based on these findings, does the sample evidence suggest that the mean number of licks required to reach the chocolate center of a Tootsie Pop is less than 364? Use the a = 0.05 level of significance." Determine the following values by rounding to the nearest indicated decimal place. Please type your solution in the text entry boxes provided. a. Mo = (Use the form XXX)

Answer 1

In this question we have to check that the mean number of licks required to reach the Center of a Tootsie pop is less than 364 - Thus the null bypothesis is Ho: le = 364 and Alternative hypothesis is He: le<364 .- Thus Ho=364 so the answer is, Ho - 364 (a) the pull hypothesis, Ho: 14 = 364 Thus the answer is: Hoe = 364 (6) the alternative hypothesis, H,: H <364 Thus the answer is He: 44<364 (C) For a sample of size 30, the mean sumber Of licks required is given to us, sample mean X = 346 Thus the answer is X=346 d) Given that We are taking a sample of 30 individuals to count the number of licks. → Sample of size, n= 30

The answer is n = 30 (e) degrees of freedom = (N-1) = (30-1) = 29 Thus the answer is df = 29 (f) Test Statistic, to- X-Ho slun Given that the sample Standard deviation, S = 176. Thus, to X-Ho 346-364 176/330 -18 0.5602 32.1331 Thus, to 0.5602 (9) Given that level of significance, d = 0.05 Thus, OC = 0.05 ta to with (n-1) df toor with 29 df

The given test is a left tailed test. Thus the critical region will be on the left tail with an area a-0.05, So the critical value will be negative toon with aq df ta = -1.699 (using Stucleot's T table) Thus, the answer is, ta = -1.699 (i) the values of t< tot -1.699 will be in the rejection region We have to check whether to <tac , if it is true then reject the null bypothesis. Otherwise clo not reject the pull bypothesis. Here to = -0.5602 tx = -1.699 Here to > ta → to is not in the critical region Shaded riegion is a 7699 0.56 So the answer is: The value of to is not in a coitical region. (j) We donot reject Ho

Since to is not in the cortical region, kle cannot reject the null hypothesis Ho. Thus the answer is, We donot reject Ho Here the citical region is on the left. Thus the test is a left tailed test. So the answer is, This was a left tailed test (f) Since the test is one failed test , It has only One critical region. Thus the answer is, There is one critical region in the associated Standard normal distribution: (M) Here we can not reject the pull hypothesis, Ho. Thus, the sample evidence does not suggest that the mean number of licks required to reach the reach the chocolate center of a Tootsie pop is less than 364. Here we are testing the population mean. so, the answer is: This was a question testing a hypothesis regarding a population mean