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OPERATIONS AND SUPPLY CHAIN MANAGEMENT L06-4 SOLVED PROBLEM 2 TASKS THAT MUST PRECEDE TASK TIME (SECONDS) 50 TASK A B С D E F

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Answer #1

Question – a:

The activity network is:

D-45 F-25 A-50 C-20 E - 20 G-10 H-35 B - 40

Question – b:

Cycle time = time available/demand

Time available = 8 hours = 8*3600 seconds = 28800 seconds

Demand = 400

Cycle time = 28800/400 = 72 seconds

Minimum number of workstations = sum total of all task time/cycle time

Sum total of all task time = (50 + 40 + 20 + 45 + 20 + 25 + 10 + 35) = 245 seconds

Minimum number of workstations = 245/72 = 3.40 = 4

Answer is: 4

Question – c:

Arranging the tasks in decreasing order of task time:

Task

Time

Predecessors

A

50

-

D

45

C

B

40

-

H

35

B, F, G

F

25

D

C

20

A

E

20

C

G

10

E

Now allotting the tasks to workstations:

Workstations Task Time A Remaining Time Idle Time 50 22 20 2 2. С D 45 27 II 2 F 25 N B 40 32 III 20 2 E G 12 2 10 IV I 35 37

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