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Lecture Exercise #13 Project Crashing Time (weeks) Cost Activity Predecessori s) Normal Crash Normal Crash A None 3 2 1000 16

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Based on the given data, we find the crash cost per week as shown below:

Activity Predecessor Crash cost per day 600 700 A B C D E F G Normal Time 3 2 1 7 6 2 4 Crash Time 2 1 1 3 3 1 2 Total Normal

Based on the predecessor relationships and normal durations given, we prepare a project network diagram as shown below:

Legend EST ID EFT SLK LST DUR LFT 0 A 3 D 10 0 - wow 0 3 3 7 10 G 14 10 0 10 B 2 E 8 4 14 0 2 2 2 2 4 14 END 14 0 14 0 14 2 4

The above network diagram in form of formulas is shown below for better understanding and reference

A C D E G H K M N O 1 2 3 B Legend ID EFT EST SLK LST 4 DUR LFT А =A6+B8 D =E6+F8 5 60 7 =A8-A6 8 =C8-B8 =C6 =E8-E6 | =G8-F8

The above project diagram is prepared as per the legend shown in the top-left corner.

EST = Early start time

LST = Late start time

EFT = Early finish time

LFT = Late finish time

SLK = Slack = LST - EST or Slack = LFT - EFT

The EST of an activity = EFT of previous activity

EFT of an activity = EST + Duration

Similarly, LFT & LST are calculated during the backward pass.

There are multiple paths in the diagram. However, path A-D-G is the longest path and has 0 slack. Hence, this is the critical path of the project.

To reduce project duration, we have to crash activities on critical path first.

As seen from above table, we start with crashing activities with minimum crash cost per day to have minimum cost impact.

As seen from the table on the top, if we want to crash the project by 1 week, we crash activity D since it has lowest crash cost per week and hence, least cost impact on the project.

We summarize the answers as shown below:

The project completion time = 30 weeks

Critical path = A-D-G

To shorten the project by 1 week, we crash activity D

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