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Question 22 2 pts A study was performed to examine the reasons for attending a college. A random sample of college students wА B D E F H K L M 1 Freshman Sophomore Junior Senior Total 2 3 4 5 6 7 Increase your earning potential Learn valuable skillsQuestion 23 6 pts Continued from the previous question: Step 2: The data are given in an Excel file Final (DATA)-Personal GoQuestion 24 2 pts Continued from the previous question: Step 3: Ignore your answers in Step 2. Assume that the P-value of the

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Answer #1
Observed Frequencies
C1 C2 C3 C4 Total
R1 44 37 55 57 193
R2 41 42 34 31 148
R3 10 19 15 7 51
R4 12 15 7 8 42
R5 8 7 12 16 43
R6 13 12 8 7 40
Total 128 132 131 126 517
Expected Frequencies
C1 C2 C3 C4 Total
R1 128 * 193 / 517 = 47.7834 132 * 193 / 517 = 49.2766 131 * 193 / 517 = 48.9033 126 * 193 / 517 = 47.0368 193
R2 128 * 148 / 517 = 36.6422 132 * 148 / 517 = 37.7872 131 * 148 / 517 = 37.501 126 * 148 / 517 = 36.0696 148
R3 128 * 51 / 517 = 12.6267 132 * 51 / 517 = 13.0213 131 * 51 / 517 = 12.9226 126 * 51 / 517 = 12.4294 51
R4 128 * 42 / 517 = 10.3985 132 * 42 / 517 = 10.7234 131 * 42 / 517 = 10.6422 126 * 42 / 517 = 10.236 42
R5 128 * 43 / 517 = 10.646 132 * 43 / 517 = 10.9787 131 * 43 / 517 = 10.8956 126 * 43 / 517 = 10.4797 43
R6 128 * 40 / 517 = 9.9033 132 * 40 / 517 = 10.2128 131 * 40 / 517 = 10.1354 126 * 40 / 517 = 9.7485 40
Total 128 132 131 126 517
(fo-fe)²/fe
R1 (44 - 47.7834)²/47.7834 = 0.2996 (37 - 49.2766)²/49.2766 = 3.0585 (55 - 48.9033)²/48.9033 = 0.7601 (57 - 47.0368)²/47.0368 = 2.1104
R2 (41 - 36.6422)²/36.6422 = 0.5183 (42 - 37.7872)²/37.7872 = 0.4697 (34 - 37.501)²/37.501 = 0.3268 (31 - 36.0696)²/36.0696 = 0.7125
R3 (10 - 12.6267)²/12.6267 = 0.5464 (19 - 13.0213)²/13.0213 = 2.7451 (15 - 12.9226)²/12.9226 = 0.3339 (7 - 12.4294)²/12.4294 = 2.3717
R4 (12 - 10.3985)²/10.3985 = 0.2467 (15 - 10.7234)²/10.7234 = 1.7055 (7 - 10.6422)²/10.6422 = 1.2465 (8 - 10.236)²/10.236 = 0.4884
R5 (8 - 10.646)²/10.646 = 0.6577 (7 - 10.9787)²/10.9787 = 1.4419 (12 - 10.8956)²/10.8956 = 0.112 (16 - 10.4797)²/10.4797 = 2.9079
R6 (13 - 9.9033)²/9.9033 = 0.9683 (12 - 10.2128)²/10.2128 = 0.3128 (8 - 10.1354)²/10.1354 = 0.4499 (7 - 9.7485)²/9.7485 = 0.7749

Q22:

Null Hypothesis:

Ho: the distribution of personal goals is the same across the class standing.

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Q23:

1. The expected value of cell corresponding to "Increase your earning potential" and "Freshman" =

= 128 * 193 / 517 = 47.7834

2. Test statistic:

χ² = ∑ ((fo-fe)²/fe) = 25.566

3. df = (r-1)(c-1) = 15

p-value = CHISQ.DIST.RT(25.5655, 15) = 0.0428

----

Q24:

At the significance level of 5% = Reject the null hypothesis. the difference is significant.

At the significance level of 1% = Reject the null hypothesis. the difference is significant.

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