ZuoTi.Pro
Question

PLEASE SHOW ALL WORK

and mass 1 A proton (Change 1.6x 10coulombs m= 1.67x1027 kg) enters magnetic field of strength B=0.5T, at angle of 30° to t

science   physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

Given 9 = 1.68109 -27 and m=1-67810 tag B=0.5T and angle = 300 det rebcity of poodon is = V (in m/s) F = e(Uxo S. Force F: Zif any inquires please comment and if you satisfied please like.

0 0
Add a comment
Know the answer?
Add Answer to:
PLEASE SHOW ALL WORK and mass 1 A proton (Change 1.6x 10''coulombs m= 1.67x1027 kg) enters...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • SHOW ALL WORK ALSO v=2X10^8 m/s and mass 1 A proton (Change 1.6x 10''coulombs m= 1.67x1027...

    SHOW ALL WORK ALSO v=2X10^8 m/s and mass 1 A proton (Change 1.6x 10''coulombs m= 1.67x1027 kg) enters a magnetic field of strength B=0.5T, at angle of 30° to the Ê field. Calculate the net force exerted on the proton by the magnetic field? B (middle) Cinder)

  • PLEASE SHOW ALL WORK 2 An electron (magnitude of its change is (q) = 1.6*109 Coulombs,...

    PLEASE SHOW ALL WORK 2 An electron (magnitude of its change is (q) = 1.6*109 Coulombs, and mass of an election me = 9.11x10² kg) enters a magnetic field of strength B= 2 x 10t Tesla, with a speed of 1.5*10%m/s perpendicularly and therefore moves in a circle. Calculate the radius of that circle.

  • 2 An electron (magnitude of its change is (q) = 1.6x109 Coulombs, and mass of an...

    2 An electron (magnitude of its change is (q) = 1.6x109 Coulombs, and mass of an election m = 9.11x103 kg) enters a magnetic field of strength B= 2 x 10t Tesla, with a speed of 1.5*108 m/s perpendicularity and therefore moves in a circle. Calculate the radius of that circle.

  • A proton moving at 8.2×106 m/s enters a magnetic field of 0.38 Tesla, with the velocity...

    A proton moving at 8.2×106 m/s enters a magnetic field of 0.38 Tesla, with the velocity vector at 90o to the magnetic field direction. Calculate the magnitude of the force exerted on the particle.

  • A proton, moving at a velocity of 681 m/s experiences an acceleration of 2.0 x 1014...

    A proton, moving at a velocity of 681 m/s experiences an acceleration of 2.0 x 1014 m/s2 when it enters a magnetic field at an angle of 55 degrees to the field. Calculate the strength of the magnetic field. Assume that the force from the magnetic field is the only force acting on the proton. (Hint: You will need to solve for this force first!)

  • please do all part a,b,c,d A particle with charge of 2 (HC), mass of 2X10-20 (kg)...

    please do all part a,b,c,d A particle with charge of 2 (HC), mass of 2X10-20 (kg) and velocity of 200(m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01x10-S(N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and magnetic field, using...

  • Please show any equation manipluation. Problem 3 A particle with charge of 2 (UC), mass of...

    Please show any equation manipluation. Problem 3 A particle with charge of 2 (UC), mass of 2x10-20 (kg) and velocity of 200 (m/s) enters into a magnetic field of 0.06 (T). The particle experiences a force of 1.01X10S(N) in the magnetic field. A) Calculate the angle between velocity and magnetic field directions. B) Calculate the acceleration of charged particle in the magnetic field. C) Draw a diagram showing direction of velocity, magnetic field, force and the angle between velocity and...

  • 8. A proton enters perpendicular to a magnetic field at 4.50 x 10 m/s that causes...

    8. A proton enters perpendicular to a magnetic field at 4.50 x 10 m/s that causes it to move in a circular path, due to a magnetic force of 1.85 x 10' N. When the proton is traveling in a circle it produces a current 1.05 x 10- A. What is the strength of the magnetic field? What is the radius of the circle? What is the torque on the proton? (16 pts)

  • A high energy proton from the sun enters the Earths magnetic field at a speed of...

    A high energy proton from the sun enters the Earths magnetic field at a speed of 6.0x10^6 m/s perpendicular to the field lines. The field is uniform and with strength B=4.5x10^-5 T. a) What is the magnetic force on the proton when it first enters the B-field? b) Calculate the radius of the protons path in the B field. c) determine the frequency and the period of the protons orbit.

  • I . A particle with the same mass and load as a proton enters a region...

    I . A particle with the same mass and load as a proton enters a region where the magnetic field has a magnitude of 4000 G. The particle moves in a circular radius trajectory of 20 cm. Determine the speed and period of the particle in the magnetic field II. A proton in a particle accelerator has a speed of 5.0 x 10^6 m / s. The proton is found with a magnetic field whose magnitude is 0.40 T and...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT