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ALSO v=2X10^8 m/s

and mass 1 A proton (Change 1.6x 10coulombs m= 1.67x1027 kg) enters a magnetic field of strength B=0.5T, at angle of 30° to

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Answer #1

Fm = q (UxB) Fm quB sind 1. Gx10 19, 2x108x 0.5 & ous sinzoo 0.8 xlo -12 8 xlo N ( out of the plane

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