Question

R134a in an ideal vapor compression heat pump generates 35 kW to heat a room. A mixture of 95% quality enters the compressor at 0.6 bar and saturated liquid exits the condenser at 14 bar. Determine: a) Mass flow rate (kg/hr) b) Compressor power (kJ/min) c) Heat transferred from outside (kW) d) Coefficient of performance

Answer 1

vapour O. 6bas as conclencer pressur Gillen! Ideal compression Hecet pump Is diagram el aporator pressure Pu=P,=0.6 beos 2 ht lubar 3 P3= P2 =lubas Quality at state, is sc: 954->0.95 ats Heat si Suppled to heat a room Heat pump by = 35kw ) 5) Dan 2) Specific enthalphy at state 1=3 h = hof to Chigh ) z hez 151-808 +0.95(375-8835-151.808) he 36406797 151kg 2) specific enthalphy at statera hz hy 2 424.25 z) specificenthalphy at states & staten hz hur he = 275-336 kileg kg rubar a) let Mass flow rateis ris) Q2z = in Chr-hz) wokot 72 358 mic 424.25-275-336) mi- 0.2303969 m= 13.823 kg mia My flow rate sec

woor = 829.41664 kglar ) Mais flow rate in kg/hr b Compressor power w:r (he-hu) 2) Wo: 023039 ( u24.25- 364.6797) zo (w 13.7246 kW 2W 823.4766 kJ/min - compressor C) Heat transfered from outside ñ Chi-hu): 6.23039 (364.6797- 215.334) 2 20.5849 Heat transfered from outside d) coefficient of performance -> for treat pump a Q23 cops 2) cop. op o cope 2:55 2 coefficient of performa Qen-1 27 Qur w 35 13.7246 E) nie of this heat pump