Question

The floor plan of a residential building is shown in Figure Q4. Assume the characteristic dead load is 4.0 kN/m2 and imposed load is 5.0 kN/m2 for all floor area. All floor slabs are of one-way slab. Determine the design loads carried by beam CD and AB Sketch the shear force diagram for beam AB indicating all salient values Total (15) marks One-way slab 3 m One-way slab с 1 1 E One-way slab 3 m Opening A 2 m 8 m

Answer 1

ANSWER :
one 15 m neway 3m 1.5m. е. X 1.5m 3m < /opening V A 8m for beam co PL = 4 kallona LL = '5 kN/m² Design load carrying capacity of floorld =. (1.359k) + 1959k =1635x4 +1.5x5 = 12.9 kN/m2 for CD beam half load from both slab LUDL: (12.9.31,5) x2 = 38.7 kN/m. 38.7 kilin Ro=154-8 KN RC = 154.8 kN. K 8m. RC=RD - 38.7x8 2 I 154. 8 KN

a B for AB k > im at CB. UDL= (12.9x1) = 12.9 kN/m ) >and in Ac.past opening as these, so no load brom that part → at a point load of beam CD will act. 1209 kN/m AB. 3 RA= 87.045 kn RB = 106,425 KAI RATRB = 154.8 t (12.9) X3 = 193.5 kn EMB=0 RAX6 - 154.843-12.983X1,5=0 IR 87.045 KNI RB = 193.5-87.045 RB = 106.455

RA = 87.045 kN. RB 106.455 KN for AB: SFD 87.045 TAS 67175 106.455