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Anode E A Cathode B 7 С D Ni2+ + 2e -0.40 V Cd2+ + 2e...
Anode E A Cathode B 7 С D Ni2+ + 2e -0.40 V Cd2+ + 2e -0.26 V Ni (s) Cd (s) Reduction Ni (8) Ereduction Cd (8) Ereduction Ni2+ (aq) Cd2+ (aq) Oxidation Salt Bridge Look at the voltaic cell diagram above and finish the following sentences using options given on the table above: i) Ais ii) B is metal on the left metal on the right solution on the left iii) Cis iv) Dis solution on the right...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
Question 13 0/1 point Given that red -0.76 V for Zn2+ Zn at 25°C, find and...
Question 13 0/1 point Given that red -0.76 V for Zn2+ Zn at 25°C, find and for the concentration cell expressed using shorthand notation below. Zn(s); Zn +1.0 10-5 M) Zn? (0.100 M) Znis) -0.00 V and E+0.24 V x 6 -0,7ổ Vard + 0,64 V -0.76 Vand E-0.52 V E = 0.00 V and E+0.12 V
Given the measured cell potential, Ecel, is -0.3657 V at 25 °C in the following cell,...
Given the measured cell potential, Ecel, is -0.3657 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)HAg, o.755 atm)lH(aq, ? M)lICd2 (aq, 1.00 M)ICd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E, are as follows. E -0.00 Vv Cd2+(aq) +2e--> Cd(s) E=-0.403 V Number H0.146
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate...
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)|H2lg, 0.795 atm)lH (aq, ? M)l|Cd2 (aq, 1.00 M)|Cd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E°, are as follows. 2H+(aq) + 2e- H2(g) E0.00 V E-0.403 V ? 2 + Number H0.21
X) The answers: a) 0.315 V c) 0.273 V d) 1.80 M 10. For the voltaic cell: Cd(s) Cd2 (0.100 M, 25 mL) || Pb2 (2.000 M, 25 mL) | Pb(s) a. What is Eel initially? (E 0.277 v) b. If the cell is allowed to...
X) The answers: a) 0.315 V c) 0.273 V d) 1.80 M
10. For the voltaic cell: Cd(s) Cd2 (0.100 M, 25 mL) || Pb2 (2.000 M, 25 mL) | Pb(s) a. What is Eel initially? (E 0.277 v) b. If the cell is allowed to operate spontaneously, will Eel increase, decrease or remain constant with time? Explain. c. What will be Ee when [Pb2"] has fallen to 0.900 M? [Hint: Both concentrations change. Why?] d. What will be [Cd2"]...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...
A Cu/Cu2+ concentration cell has a voltage of 0.24 V at 25 ∘C. The concentration of...
A Cu/Cu2+ concentration cell has a voltage of 0.24 V at 25 ∘C. The concentration of Cu2+ in one of the half-cells is 1.6×10−3 M . What is the concentration of Cu2+ in the other half-cell? (Assume the concentration in the unknown cell to be the lower of the two concentrations.) Express your answer using two significant figures.
1. Some standard reduction potentials at 25 C are: E 0.337 V for Cu* (a) 2e- Cu(s) E" =-0.1 26 V ...
1. Some standard reduction potentials at 25 C are: E 0.337 V for Cu* (a) 2e- Cu(s) E" =-0.1 26 V for Phẩ (aq) + 2e → Pb(s) Eo-0.763 V for Zn2 (a)2e-> Zn(s) Predict the voltage of each of the following voltaic cells: a. Cu | Cu0.010 M)I Cu (0.010M) | Cu c. Zn | Zn2 (0010 M) Cu(0.010 M) | Cu b. Pb | Pb (0.010 M)1 Cu (0.010 MCud. Zn | Zn3 (0.010 M) 11 Pb (0.010...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g)...
Use the tabulated electrode potentials to calculate K for the oxidation of nickel by H+: Ni(s)+2H+(aq)→Ni2+(aq)+H2(g) Express your answer using two significant figures. Standard reduction half-cell potentials at 25∘C Half-reaction E∘ (V) Half-reaction E∘ (V) Au3+(aq)+3e−→Au(s) 1.50 Fe2+(aq)+2e−→Fe(s) −0.45 Ag+(aq)+e−→Ag(s) 0.80 Cr3+(aq)+e−→Cr2+(aq) −0.50 Fe3+(aq)+3e−→Fe2+(aq) 0.77 Cr3+(aq)+3e−→Cr(s) −0.73 Cu+(aq)+e−→Cu(s) 0.52 Zn2+(aq)+2e−→Zn(s) −0.76 Cu2+(aq)+2e−→Cu(s) 0.34 Mn2+(aq)+2e−→Mn(s) −1.18 2H+(aq)+2e−→H2(g) 0.00 Al3+(aq)+3e−→Al(s) −1.66 Fe3+(aq)+3e−→Fe(s) −0.036 Mg2+(aq)+2e−→Mg(s) −2.37 Pb2+(aq)+2e−→Pb(s) −0.13 Na+(aq)+e−→Na(s) −2.71 Sn2+(aq)+2e−→Sn(s) −0.14 Ca2+(aq)+2e−→Ca(s) −2.76 Ni2+(aq)+2e−→Ni(s) −0.23 Ba2+(aq)+2e−→Ba(s) −2.90 Co2+(aq)+2e−→Co(s) −0.28 K+(aq)+e−→K(s) −2.92 Cd2+(aq)+2e−→Cd(s)...
Anode E A Cathode B 7 С D Ni2+ + 2e -0.40 V Cd2+ + 2e -0.26 V Ni (s) Cd (s) Reduction Ni (8) Ereduction Cd (8) Ereduction Ni2+ (aq) Cd2+ (aq) Oxidation Salt Bridge Look at the voltaic cell diagram above and finish the following sentences using options given on the table above: i) Ais ii) B is metal on the left metal on the right solution on the left iii) Cis iv) Dis solution on the right...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...
Question 13 0/1 point Given that red -0.76 V for Zn2+ Zn at 25°C, find and for the concentration cell expressed using shorthand notation below. Zn(s); Zn +1.0 10-5 M) Zn? (0.100 M) Znis) -0.00 V and E+0.24 V x 6 -0,7ổ Vard + 0,64 V -0.76 Vand E-0.52 V E = 0.00 V and E+0.12 V
Given the measured cell potential, Ecel, is -0.3657 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)HAg, o.755 atm)lH(aq, ? M)lICd2 (aq, 1.00 M)ICd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E, are as follows. E -0.00 Vv Cd2+(aq) +2e--> Cd(s) E=-0.403 V Number H0.146
Given the measured cell potential, Ecell, is-0.3583 V at 25 °C in the following cell, calculate the Ht concentration Pt (s)|H2lg, 0.795 atm)lH (aq, ? M)l|Cd2 (aq, 1.00 M)|Cd (s) The balanced reduction half-reactions for the cell, and their respective standard reduction potential values, E°, are as follows. 2H+(aq) + 2e- H2(g) E0.00 V E-0.403 V ? 2 + Number H0.21
X) The answers: a) 0.315 V c) 0.273 V d) 1.80 M
10. For the voltaic cell: Cd(s) Cd2 (0.100 M, 25 mL) || Pb2 (2.000 M, 25 mL) | Pb(s) a. What is Eel initially? (E 0.277 v) b. If the cell is allowed to operate spontaneously, will Eel increase, decrease or remain constant with time? Explain. c. What will be Ee when [Pb2"] has fallen to 0.900 M? [Hint: Both concentrations change. Why?] d. What will be [Cd2"]...
Standard reduction half-cell potentials at 25°C E (V) E (V) 1.50 -0.45 0.80 -0.50 0.77 -0.73 0.52 -0.76 0.34 -1.18 Half-reaction Aut (aq) + 3e +Au(s) Ag+ (aq) + +Ag(s) Fe3+ (aq) +34 Fo+ (aq) Cut(aq) + Cu(s) Cu²+ (aq) + 2e +Cu(s) 2H+ (aq) - 2e +H2 (6) Fe3+ (aq) + 3e Fe(s) Pb2+ (aq) + 2e →Pb(s) Sn-(aq) + 2e +Sn(s) Ni2+ (aq) + 2e →Ni(s) Co2(aq) +2e + Co(s) ca? (aq) + 2e +Cd(s) 0.00 Half-reaction Fe(aq)...
1. Some standard reduction potentials at 25 C are: E 0.337 V for Cu* (a) 2e- Cu(s) E" =-0.1 26 V for Phẩ (aq) + 2e → Pb(s) Eo-0.763 V for Zn2 (a)2e-> Zn(s) Predict the voltage of each of the following voltaic cells: a. Cu | Cu0.010 M)I Cu (0.010M) | Cu c. Zn | Zn2 (0010 M) Cu(0.010 M) | Cu b. Pb | Pb (0.010 M)1 Cu (0.010 MCud. Zn | Zn3 (0.010 M) 11 Pb (0.010...
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