Give the organic products of the reactions. INCLUDE
STEREOCHEMISTRY & REGIOSPECIFICITY.
CH3 CH,CH2CCH2C CH 2 HBr CH3 Pd/BaSO4 C C H2 Pt + 2D2 CH3(CH2)3C CH Na Ph-C C-Ph NH3 1) (CH3)C-O NANH 2) H2O CH,C CH
CH3 CH-CH=CH-CH3 + HBr CH3 Draw the molecules on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Ht 12D н C
Give the organic products, with the CORRECT REGIOCHEMISTRY AND
STEREOCHEMISTRY, when appropriate. !!!
CH3 -C CH-CH + HI Нас CH2OOCH C CH-CH2CH3 +HBr Pd + D2 CH3 Но C CH- CH2CH3 Н-о + Нас 1) (BH3)2, THF 2) H-0,. ОН" Cн, Н.о" CH3CO;H CH3 CHCI/ KOH cCH Hас H +Cl2
Can someone explain why this
was not added Markonikov?
31. HBr ether CH-CH· CH3
Classify each of the following organic reactions. Addition CH3-CH2-CH-CH3 – CH3-CH2-CH=CH2 + HCI CH3-C-O-CH3 + CH3-NH-CH3-C-NH-CH3 + CH2-OH CH3-CH2-CH2-OH + HBr -- CH3-CH2-CH2-Br + H20 Elimination OH CH2-CH + HCN – CH3-CH-CN CH3-CH=CH-CH3 + HBr + CH3-CH-CH2-CH3 Br Substitution CH3-CH2-CH2-CH3 + Cl2 → CH-CH2-CH2-CH3 + HCI СІ CH3-CH=CH-CH3 + Cl2 - CH3-CH-CH-CH3 CICI Reset
Post Lab questions 1. Complete the following reactions and name the products. CH3 -CH=CH2 + CI + Brz c) CH3 -CH=CH-CH, + HBr - Pt d) CH3 -CH2-CH=CH2 + H 25 °C, I am A Bez 2. Toluene contains a benzene ring with three double bonds in it, but still does not show any signs of undergoing a reaction with bromine solution. Why? 3. Why doesn't cyclohexane decolorize the orange-red color of the bromine or the purple color of KMnO...
towards HBr ! CH3 10) whichy Compound is most recictive - HG A.HzC= CH- H3C vita C. H₂C=CH-
towards HBr ! CH3 10) whichy Compound is most recictive - HG A.HzC= CH- H3C vita C. H₂C=CH-
Question 35 1 pts What are the products of the reaction of the following reaction? CH-CH3-N-CH-CH3 + NaOH→ | CHỊ-CH-W-OH + CH3CHẠNH, CH3-CH -CH - O Na+ + CH3CH2NH3 +Cl- CH-CH-CH-OH + CH CHANH + Naº CHI-CH-Bo Na + CH,CHÁNH,
What two products are expected in the following reaction? CH; HBr H H Br CH CH CH Br H BI II III H Br H BI CH; CH; IV