Question

Question 3 CIRCUIT B1 (2.5 Marks) + Vcc Rc IRC > IC RB Ів + VCE IE FIG. 3: CIRCUIT B1 Statement: Sketching relevant output (Vc-Ic) characteristics decide on Q-point coordinates and DC load-line details: That is, determine DC operating conditions of the NPN-BJT/Si circuit of Fig.3 (denoting the type Circuit B1). Assume the following: Vcc= 20 volt; Rc = 2.5 k; RB = 350 k and B = 100. Required Solutions In the multiple choice of answers supplied, choose the correct set of results on quiescent values representing: {VCE, Emitter-collector voltage; IE, Emitter current; Ic, Collector current; Irc, Current drawn from supply; IB, Base current}. (1) {VCE = 10 volt; IE = 4.326 mA; Ic = 4.299; Irc = 5.262 mA; 1b = 42.25 uA}. (2) {Vce = 12 volt; Ig = 3.326 mA; Ic= 1.399; Irc = 1.262 mA; IB = 32.29 uA}. (3) {VCE = 11 volt; IE = 4.326 mA; Ic = 4.299; Irc = 3.262 mA; IB = 22.35 uA}. (4) {VCE = 12 volt; IE = 3.326 mA; Ic= 5.299; Irc = 5.262 mA; 1B = 32.23 uA}. (5) {VCE = 12 volt; IE = 3.326 mA; Ic= 3.299; Irc = 3.261 mA; IB = 32.29 uA}.

please choose one of the answer choices above.

Must show all work, thank you

Answer 1

solution it siven circut is- Given data- tvec Vcc= २०V Ircd Rc Rc = 2.5k RB = 3 SOK He Ic IB) i Re B = 100 k NCE we know that VBE = 0.7V IE (VE =o) ande VE (grounded re inner loop in K.V.L Apply - Vec + (The' Rc) + (IG RB) + VBE = t + - Vcc + (Fot Ic) Ret IBRB Wee = 0 (: IR = Ist I ☆ -Vec + IcRc + FB ( Rotfc) & UBE V - Vect IB ( Ret Ret Bre) + VBE 20 Ic=BIB) Vcc VBE IB Vcc - VBE 3 ) (Rot Rc+BRc) Rot (B+1) RC 个 putting all the Values- 20-0.7 19.3 IB = (350k) + (100+1) 2.5k (350k) + (25265 k) 19.3 19.3 x(103) 19300 MA = IQ = 602.5 602.5K 602.5x (105)

MA IB = 32.03 D 3.2 mA 3203.MA 100 x 32.03 MA Ic = B IB Ic= 3.2 ma lol x 32103 MA (100+1) 32.03 MA = * I E = (B+1) Il a we know that TE = 3·235 MA Io Z IC LIE ZIE) 3·235 mA x IRC Ist Ica IE = Ire 3.235 MA Loop : in outer * KINOL Apply -Ncct (IRCRC) + VCE do- (3.235 m) (disk) VCE Vcc - (TecRc) VCE = 11.9 20- 8.08 20 – (3-235 x 2,5) = VCE = 12v are Valuer Calculated Exact. these values. Check Option that is 7 near to i.e. option (5) IE= 3•326 MA Ic= 2 3•299 MA VCE > 1QY 个 IRC 3.261 mA Ig = 32.29 MA
All the calculated values are exact. Check the option that is nearer to the values (Option - 5)