Question

*10–32. Determine the moment of inertia I, of the shaded area about the x axis. 10–33. Determine the moment of inertia Ix of the shaded area about the y axis. у |-100 mm 100 mm-f-150 mm 150 mm 150 mm 75 mm X Probs. 10–32/33
please keep the solution short.

Answer 1

Given: 4100mm. y. 100 malle 150 150m 150mm To find : Shaded portion about axis (in moment of inertia Moment Y anu of about Inertia Solution : about a ais tind Ihootia portion moment Shaded of Ix + Iz Iz - 3 moment of thertia of hectangle + m.l.q triangle M.J. of circle bd3 3 2004 366 = 108 109 mmh 3 3 L mmy bh3 1501 3003 3.37x108 11 se le te what 12 12 + [on + [1] I - Day 64 2 04878 110 mmy Fx1504 + [5x752 +150² 64 IX - 1.84109 + 3.37x108 (2.4818 x 107) Ix 2.12 109 mmy

To find moment of inertta about 4 axis Ty I + I - I T. bd3 3004 2003 80 108 mmy 3 3 T. 3 300 150 - 8.437 x 107 month 12 2 13 rid [117*th'] 70*1504 + (19*75%) +100 64 64 2.4901 x 107 mmh Iy I, & I - I3 Iy 8.5946 X 168 mm Result: Moment In Inertia of Portion Ix= 2.12 x 100 mm Shaded about x aris Moment of Inertia 8.594 x 10° mmy shaded Portion about 4 ans