Question

A concentric-pipe parallel-flow heat exchanger is to heat water (cp = 4.18 kJ/kg.K) from 20°C to 80°C at a rate of 1.2 kg/s.
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Answer #1

Sos: parallel flow :- ma :21g1s , Q=14. 31 kJ/kg.k The = 160 The 80 = The = 1-2 kg/s! Ta = 20 Q: 4-18191 kg U= 640 W/mK (1) U5:016 0,582 (m(p) small (mcp) big 8.62 > (nice) hot if (m (p) cold (1 cp) cold L (mcp) Hot if EE Thi The The Tce E The -Tu Thboth sides : on Taking Natural log 1.582 NIU en (0.32.29) en [ ē wtu] - -1.582 NTU -1:13 NTU - 0.714 640 X A 0.714 NIU 5.016

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