Question

Aroadway sign that weighs Py = 6 kN is supported by a structural pipe with an outside diameter of 320 mm and a wall thickness of 12.5 mm. Wind pressure on the sign creates a resultant force of Pz - 18 kN, acting as shown. Using length dimensions of a -4.7 m and b = 6.3 m, determine (a) the normal and shear stresses at point H. (b) the normal and shear stresses at point K. P H K Answers: (a) Point H: 0x MPa MPa MPa Txy (b) Point Koy 0,"i MPa MPa Tyz MPa

Answer 1

Stresses @ Point #!? 20. Solution: Considering the diagrams in that ņa ។ C/ Area.g Pile = A dd) 7 (32ő - 820104 Free body diagram My = 37.8 kn-m 6157.34mm 11 3.4 kw.m= Tz 63 y. H Puc olan Py = bkn cy 12 - 18 kn .:@ Point H P=18kw. Py X4 7x 160 My Stress due Oy - + Therefore by Converting the above diagram to My=0 as H@NA I Tension My = 15x6-3 Compression (P2 x 6-3) = Tz -6000 18000x 4700x160x14 . + Py = 6low 6157.34 P2=18kw XX3204 -0874 + 26-31 = 25-33N N/mm = Ty We Converted the + Py force into Py normal and (Pyx63 ) Moment: Same way Pz into Pz force and ( P2 x 6-3) Joque. Zay Tz XR J ASO (oa Ib. o'as His@ Torsion due to Neutsai anus Tz

Strennes @loime t'i :: Zayn My = }}'.$ J 1134xlol x 10 * 32 . fm ni Lys 1 blond g Pa 18 kn X x 3204 = 17.63 N/mm Any = 17.63 N/mm v @k -Py y= + My xy) t (1959) t 11 70 A o (compression Book is NA 용 on . @ Point '#' gy = 25-33 N/mm Tay = 17.63 N/mm. Garfsevolen Temion due to my@k -6000 32.8x10 x 160464 + 6157.34 Tx3204 -0.976 + 11.75 10.78N/mm lay= 10.78 N/mmy 1

Tony = (Text) tege Tovarende) Maa Shear stress due to vertical load 113-61X/06x160x32 + TX 3204 Hy 18000 -Х 6157.34 = 17.63 + 3.89 Zay=-2152 N/mm (negative as los ..@ Point k direction O oy 10.78 W/mm Try .-21.52 N/mmv
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